All categories

3 years ago

Will mark brainiest answer ASAP

Mathematics

1 answer:

Vlad1618 [11]3 years ago

5 0

You're just simply multiplying them by 2 because the scale factor being applied is 2. So..

P' Q' = 4 cm
A' B' = 3 cm
M' N' = 6 cm

You might be interested in

I can’t find this answer, help me plss

Vinvika [58]

2) 7/4×(22–x) =0

soln

= 7/4×(22 –x) =0

= 1.75 ×22 –x =0

= x=38.5

9) 15x² /7 =8x²/5

soln

= 15x²×8x²=7×5

=120x^4 = 35

= x^4 =120–35

x^4 =85

6) 9x²/4–4=0

soln

=9x²/4–4=0

=2.25–4=0

=4–2.25=0

=1.75

<h2>sorry I know that much </h2>

8 0

2 years ago

1 - Graph a line with a slope of 4

AVprozaik [17]

Y=4x+2 that my equation now graph it

4 0

2 years ago

Solve for x with a degree of 30 & side of 300ft

tankabanditka [31]

Answer:

x = 100√3

Step-by-step explanation:

tan(30º) = x/300

x = 300 tan(30º)

x = 300/√3

x = 100√3

3 0

3 years ago

10. In a warehouse, the workers sometimes slide boxes along the floor to move them. Two boxes

RSB [31]

Answer:

The Box 1 and Box 2 are the same mass.

Explanation:

It caused both to change speed because they have both the same mass.

7 0

2 years ago

Alejandra's Tapas Bar offers a menu consisting of $9$ savory and $5$ sweet dishes. You can also get a mix-and-match plate consis

Mariana [72]

Answer:

Step-by-step explanation:

Given that the number of savory dishes is 9 and the number of sweet dished is 5.

Denoting all the 9 savory dishes by $p_1, p_2,...,p_9$ , and all the sweet dishes by $q_1,q_2,...,q_5$ .

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with $q_1$ from sweet plates which are $(q_1, p_1), (q_1, p_2), ..., (q_1,p_9).$

There are 9 plates with $q_2$ from sweet plates which are $(q_2, p_1), (q_2, p_2), ..., (q_2,p_9).$

Similarly, there are 9 plated for each $q_3, q_4$ and $q_5.$

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

$= 9+9+9+9+9= 9\times5=45$

7 0

3 years ago