The answer is fifty four hundredths
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
I think 30
Step-by-step explanation:
Using the Pythagorean theorem:
a^2 + b^2 = c^2
A and B are the sides and c is the hypotenuse.
4^2 + 5^2 = c^2
Simplify:
16+25 = c^2
41 = c^2
Take the square root of both sides:
c=√41
Answer:
Step-by-step explanation:
The answer is b trust me
