The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Answer:
1. -12x^8
2. 8x^6
3. 16x^11
Step-by-step explanation:
Answer:
1 1/5
Step-by-step explanation:
1 and 1 fifth as a fraction.
Answer:
80 blue
Step-by-step explanation:
r=red
b=blue
4b+2r=6 lights in one light cluster
120/6=20 clusters
20 clusters of 4 blue lights =80
Answer:
B)
B)
D)
Step-by-step explanation:
1. 
The GCF of all the term of the above polynomial is 
, hence we take it outside and form a bracket
The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer
2. 
The GCF of all the term of the above polynomial is 
, hence we take it outside and form a bracket
The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer
3. 
The GCF of all the term of the above polynomial is 
, hence we take it outside and form a bracket
The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer
