The stable nuclide ²⁰⁶₈₂Pb is formed from ²³⁸₉₂U by a long series of α and β⁻ decays. Which of the following nuclides could NOT
be involved in this decay series?
A) Th-234
B) U-239
C) Po-218
D) Bi-214
E) Rn-222
2 answers:
Answer:
Rn-222
Step-by-step explanation:
this decay takes specified step therefore Rn-222is not a decaying process
Answer:
B) U-239 is the answer
hope it helps you
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Step-by-step explanation:
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Step-by-step explanation:
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