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Andrews [41]
2 years ago
9

The stable nuclide ²⁰⁶₈₂Pb is formed from ²³⁸₉₂U by a long series of α and β⁻ decays. Which of the following nuclides could NOT

be involved in this decay series?
A) Th-234
B) U-239
C) Po-218
D) Bi-214
E) Rn-222
Mathematics
2 answers:
Makovka662 [10]2 years ago
8 0

Answer:

Rn-222

Step-by-step explanation:

this decay takes specified step therefore Rn-222is not a decaying process

Lana71 [14]2 years ago
6 0

Answer:

B) U-239 is the answer

hope it helps you

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3 years ago
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