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Andrews [41]
3 years ago
9

The stable nuclide ²⁰⁶₈₂Pb is formed from ²³⁸₉₂U by a long series of α and β⁻ decays. Which of the following nuclides could NOT

be involved in this decay series?
A) Th-234
B) U-239
C) Po-218
D) Bi-214
E) Rn-222
Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

Rn-222

Step-by-step explanation:

this decay takes specified step therefore Rn-222is not a decaying process

Lana71 [14]3 years ago
6 0

Answer:

B) U-239 is the answer

hope it helps you

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(23/5) divided (-33/4)
Romashka [77]

Step-by-step explanation:

(23/5)÷(-33/4)

multiply the first by the second reverse

23/5×4/-33

multiply the numerator between them and the denomination between them

92/-165

-0.558

5 0
3 years ago
Find the length of side a.<br> 10<br> A<br> 6<br> A. 4<br> B. 64<br> C. V 136<br> D. 8<br> PREVIOUS
dedylja [7]

Answer:

D .8

Step-by-step explanation:

hypotenuse (h) = 10

base (b) = 6

perpendicular (p) = a= ?

We know by using Pythagoras theorem we get

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a = √ 64

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Hope it will help :)

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2 years ago
What graph is p less than or equal to -1
Montano1993 [528]
Dont know,not sure of this one
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3 years ago
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bearhunter [10]
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3 0
3 years ago
8.21 - 5.19 =<br> Plz show work
elena-s [515]

Answer:

3.02 is the answer

Step-by-step explanation:

BTW, study today! I'm so mad bro

6 0
3 years ago
Read 2 more answers
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