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3 years ago

Which quadrants does the line representing the equation y = 6x pass through?

Mathematics

1 answer:

Maslowich3 years ago

7 0

1,3 should be the coordinates. I believe from the graph that has been given in the question

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Solve the inequality for 8w-35< 3−(5-4w) Simplify the answer as much as possible

Finger [1]

Answer:

w<33/4

Step-by-step explanation:

8w-35<3-(5-4w)

8w-35<3-5+4w

8w-35<-2+4w

8w-4w-35<-2

4w-35<-2

4w<-2+35

4w<33

w<33/4

7 0

3 years ago

What is the side length, in inches, of the pets

tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is $4x-5$ inches

Step-by-step explanation:

Given

Area of the square of design = $16x^{2} -40x+25$

First we find the roots of equation $16x^{2} -40x+25=0$

The roots of the quadratic equation $ax^{2} +bx^{2} +c=0$ are given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where $a=16, b=-40, c=25$

$x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}$

$x=\frac{40\pm\sqrt{1600-1600}}{32}$

$x=\frac{40\pm\sqrt{0}}{32}$

$x=\frac{40}{32}$

$x=\frac{5}{4}$

$4x=5\\4x-5=0$

That is, the factors of the polynomial $16x^{2} -40x+25$ are $4x-5$ and $4x-5$ .

So, Area of the square design = $16x^{2} -40x+25$ = $(4x-5)^{2}$

Area of a square = Length^2

Thus, the length of the sign is $4x-5$ inches

7 0

3 years ago

I need to know the answer

guapka [62]

9! good luck skdjdjd

4 0

2 years ago

Read 2 more answers

Go to Canvas to watch an instructional video and complete the assignment. After watching the video and uploading the assignment

Reptile [31]

This is simply what I wrote for my assignment, sorry I am a bit late.

It was confusing when she took out the negative and postive pairs, but then I soon knew that the negative tiles are like subtracting positive tiles. Then once she got the total I was amazed with how easy it was to find out the value of x.

hope this helps! <3

7 0

2 years ago

The rectangular coordinates of a point are given. Find the polar coordinates (r,theta) of this point with theta expressed in r

alexandr402 [8]

Answer:}

In polar coordinates P is

P ( 12 ; 2.618 )

Step-by-step explanation:

The point (ectangular coordinates)

P ( -6√3 ; 6 ) P ( x ; y )

Polar coordinates P ( r ; θ )

x = r cos θ

y = r sin θ r > 0 and 0 ≤ θ ≤ 2π

Then

r = √ (x)² + (y)² r = √(36)²*3 +( 36)² r = √144

r = 12 (hypothenuse module always positive)

The point P ( -6√3 ; 6 ) is in second cuadrant between 90° and 180°

angle between r and horizontal axis x is equal to θ

tan α = l.opp/ l.adj. tan θ = y/x tan θ = - 6 /6√3

tan α = - 1/√3

Then α = 180⁰ - 150⁰ = 30⁰ or θ = 150⁰

to express that value in radians we have :

1 π radian = 180⁰ ⇒ 3,1416 radians = 180⁰

x ?? = 150⁰

x = radians

Finally the point is P ( 12 ; 2.618 )

6 0

2 years ago