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seropon [69]
3 years ago
8

Amanda is riding her bicycle. she rides at a speed of 11 kilometers per hour for 17.6 kilometers. for how many hours does she ri

de?
Mathematics
1 answer:
fenix001 [56]3 years ago
4 0
Speed=distance / time    ⇒ time=distance / speed.

Data:
distance=17.6 km
speed=11 km/h.

Therefore:
Time=17.6 Km / (11 Km/h)=1.6 hours

Answer: 1.6 hours.
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5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
Evaluate y = 2x + 1 when x= -1
Stolb23 [73]
Y = 2x + 1
y = 2(-1) + 1
y= -2 + 1
y= -1
5 0
2 years ago
Read 2 more answers
The area of the scale model of a playground is 6 square yards. The scale model is enlarged by a scale factor of 3 to create the
REY [17]

Answer:

B: 54 square feet

Step-by-step explanation:

There are 3 feet in 1 yard. The scale model is 6 square yards.

Multiply 6 by 3 to get the amount of square yards.

There are 18 square yards in the actual playground.

Since there are 3 feet in a yard, multiply 18 by 3.

This gives you your answer:

54 square feet

6 0
3 years ago
Read 2 more answers
What is 3a+22.5h*37q? im lost plz help
erik [133]
The answer is 185hq+3a
7 0
2 years ago
Could someone please explain how to solve for the area?
mixas84 [53]

9514 1404 393

Answer:

  779.4 square units

Step-by-step explanation:

You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.

One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...

  A = (1/2)r²sin(α)

Since there are n such triangles, the area of the n-gon is ...

  A = (n/2)r²sin(360°/n)

__

For a hexagon (n=6) with radius 10√3, the area is ...

  A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units

8 0
2 years ago
Read 2 more answers
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