Answer:
There are an absolute minimum (x = 6) and an absolute maximum (x = 12).
Step-by-step explanation:
The correct statement is described below:
Find the absolute maximum and minimum values of the function below:
, 
Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.
First, we obtain the first derivative of the function and equalize it to zero:


(Eq. 1)
As we can see, only a solution is a valid critical value. That is: 
Second, we determine the second derivative formula and evaluate it at the only critical point:
(Eq. 2)
x = 6

(Absolute minimum)
Third, we evaluate the function at each extreme of the given interval and the critical point as well:
x = 2


x = 6


x = 12


There are an absolute minimum (x = 6) and an absolute maximum (x = 12).
Answer:
(4, 7)
Step-by-step explanation:
The point of interest is ...
P = (2Z +1Y)/(2+1) = ((2·3+6)/3, (2·9+3)/3)
P = (4, 7)
__
The point that divides the segment into the ratio a:b is the weighted average of the endpoints, with the weights being "b" and "a". The weight of the first end point corresponds to the length of the far end of the segment.
Answer:120
Step-by-step explanation:
Answer:

Step-by-step explanation:
Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operation and stands for:
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
First, add 3 to both sides of the equation:
u = -3a - 3
u (+3) = -3a - 3 (+3)
u + 3 = -3a
Next, divide -3 from both sides of the equation:
(u + 3)/-3 = (-3a)/-3
a = (u + 3)/-3
is your answer.
~