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3 years ago

If the car spends 2.5 hours going 35 miles per hour on the trip, how long does it spend going 35 miles per hours

Mathematics

1 answer:

Neporo4naja [7]3 years ago

6 0

its spends 2.5 hours going 35 miles per hour. so the answer is 2.5 because 35 miles as you said goes 2.5 hours

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Hanna picks up strawberries. she can either choose getting 74$ per hour or 3 $ per basket. she says she can pick up 10 basket in

FinnZ [79.3K]

Answer:

21.62% more

Step-by-step explanation:

20 mins * 3 = 60 mins (1 hour)

10 baskets * 3 = 30 baskets

3$ * 30 baskets = 90$

90$ - 74$ = 16$

74 / 100 - 0.74

90 / 0.74 = 121.62

So she makes 21.62% more with 3$ per basket.

8 0

3 years ago

The adult admission price to the amusement park increased from $35 last year to $42 this year.what is the rate of inflation?

Mrrafil [7]

Answer:7

Step-by-step explanation:

42-35=7

6 0

2 years ago

Ms. Daffy tells you that the longest side of her right-triangular garden is 26m and one of the sides is 14m. A. She asks you to

ira [324]

Answer:

22m

Step-by-step explanation:

The computation is shown below:

Since it is a right-triangular garden so we use the pythagoreus theorem

As we know that

The C^2 refers to the longest side of the right-triangular garden

So,

a^2 + b^2 = c^2

a^2 + 14^2 = 26^2

a^2 + 196 = 676

a^2 = 480

So a = 22m

Hence, the other side of the garden is 22m

6 0

3 years ago

7. The following clues are given about a bucket of bubble gum.

scZoUnD [109]

There were 472 pieces of bubble gum in the bucket

Step-by-step explanation:

The following clues are given about a bucket of bubble gum

1. There are between 400 - 500 pieces of gum in the bucket

2. The bubble gum was purchased in 4 equally-sized bags

3. The product of all the digits is 56

Let us explain how to solve the problem

∵ The number of the pieces of gum is between 400 and 500

∴ The number of pieces is 3-digit number and its hundred digit is 4

∵ The product of all digits is 56

∵ One of the digit is 4

∵ 56 ÷ 4 = 14

∴ The product of the ten digit and the one digit is 14

∵ 14 = 2 × 7

∴ The ten digit and the one digit are 2 and 7 or 7 and 2

- If the ten digit is 2 and the one digit is 7

∴ The number of pieces is 427

∵ The bubble gum was purchased in 4 equally-sized bags

- That means there were 4 pieces of bubble gum in each bag

∴ The number of pieces must divisible by 4

- The number is divisible by 4 if it is an even number and the number

formed from the ten digit and one digit is divisible by 4

∵ 427 is an odd number

∴ 427 not divisible by 4

- If the ten digit is 7 and the one digit is 2

∴ The number of pieces is 472

∵ 472 is an even number

∵ 72 divisible by 4

∴ 472 is divisible by 4

∴ There are 472 pieces of gum in the bucket

There were 472 pieces of bubble gum in the bucket

Learn more:

You can learn more about digits in brainly.com/question/547255

#LearnwithBrainly

7 0

3 years ago

Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess

Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2$

4 0

2 years ago

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