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Gala2k [10]
3 years ago
6

The length of the radius of a circle with an area of 100 yards is yards.

Mathematics
1 answer:
love history [14]3 years ago
5 0

Answer:

r≈5.64

Step-by-step explanation:

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It takes Billy 40 minutes to drive to his friends house at his normal speed but it takes two hours if he drives 20 mph slower ho
bulgar [2K]

Answer:

Step-by-step explanation:

d/t=mph

8 0
2 years ago
1/X+4 = 5 it is solving rational equations
finlep [7]
X=1
Subtract four so you get 1/x=1
Multiply by x
1x=1
Divide by 1
7 0
3 years ago
Brian's gross earnings for the week of July 8, 2019, are $1227.38. His deductions comprise 23% of his total compensation.
artcher [175]

Question is Incomplete;Complete question is given below;

Brian's gross earnings for the week of July 8, 2019, are $1227.38. His deductions comprise 23% of his total compensation.

What is his net pay?

Enter the answer to the nearest hundredth, such as $1234.56.

Answer:

Brian's Net pay is $945.08.

Step-by-step explanation:

Given:

Gross earnings for the week = $1227.38

Deductions = 23%

We need to find the net pay.

Solution:

First we will find the amount deducted.

amount deducted is equal to Deductions on Gross pay.

framing in equation form we get;

amount deducted = \frac{23}{100}\times 1227.38 = \$282.2974

Now we can say that;

Net pay is equal to Gross earnings minus amount deducted in tax.

framing in equation form we get;

Net pay = 1227.38-282.2974 = \$945.0826

Rounding to nearest hundred  we get;

Net pay = $945.08

Hence Brian's Net pay is $945.08.

6 0
3 years ago
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
3 years ago
Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
zzz [600]

Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}

7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

6 0
3 years ago
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