The length of the radius of a circle with an area of 100 yards is yards.

It takes Billy 40 minutes to drive to his friends house at his normal speed but it takes two hours if he drives 20 mph slower ho

bulgar [2K]

Answer:

Step-by-step explanation:

d/t=mph

8 0

2 years ago

1/X+4 = 5 it is solving rational equations

finlep [7]

X=1
Subtract four so you get 1/x=1
Multiply by x
1x=1
Divide by 1

7 0

3 years ago

Brian's gross earnings for the week of July 8, 2019, are $1227.38. His deductions comprise 23% of his total compensation.

artcher [175]

Question is Incomplete;Complete question is given below;

Brian's gross earnings for the week of July 8, 2019, are $1227.38. His deductions comprise 23% of his total compensation.

What is his net pay?

Enter the answer to the nearest hundredth, such as $1234.56.

Answer:

Brian's Net pay is $945.08.

Step-by-step explanation:

Given:

Gross earnings for the week = $1227.38

Deductions = 23%

We need to find the net pay.

Solution:

First we will find the amount deducted.

amount deducted is equal to Deductions on Gross pay.

framing in equation form we get;

amount deducted = $\frac{23}{100}\times 1227.38 = \$282.2974$

Now we can say that;

Net pay is equal to Gross earnings minus amount deducted in tax.

framing in equation form we get;

Net pay = $1227.38-282.2974 = \$945.0826$

Rounding to nearest hundred we get;

Net pay = $945.08

Hence Brian's Net pay is $945.08.

6 0

3 years ago

A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st

Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

X = an US adult who does not uses social media.

Y = an US adult between the ages 18 and 29.

Z = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (X')) = 1 - P (US adult so not use social media)

$=1-P(X)\\=1-0.35\\=0.65$

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (Y)) = 1 - P (Adults 30 or above)

$=1-P(Z)\\=1-0.78\\=0.22$

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

$=0.22+0.65-0.672\\=0.198$

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0

3 years ago

Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).

zzz [600]

Answer:

F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

Step-by-step explanation:

We have given $F(S)=\frac{7e^{-7s}}{s^2-49}$

Now $F(S)=e^{-7s}G(s)$

Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

$\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}$

$7=A(S-7)+B(S+7)$

On comparing the coefficient

$A=\frac{1}{2}$ and $B=\frac{-1}{2}$

On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

6 0

3 years ago