Plot the image of point C under a dilation about the origin (0,0) with a scale factor of 1/5

5 3/4 times 1 3/4 and simplified

mrs_skeptik [129]

Answer:

I believe the answer will be 27/3

3 0

3 years ago

How many pound are in 28 ounces

krok68 [10]

Answer:

1.75

Step-by-step explanation:

Divide the ounces by 16 to get the value.

3 0

3 years ago

What is the answer to this solution. -7r−4≥ 4r+2

tia_tia [17]

Answer:

The solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

$-7r-4\ge \:4r+2$

Add 4 to both sides

$-7r-4+4\ge \:4r+2+4$

Simplify

$-7r\ge \:4r+6$

Subtract 4r from both sides

$-7r-4r\ge \:4r+6-4r$

Simplify

$-11r\ge \:6$

Multiply both sides by -1 (reverses the inequality)

$\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)$

Simplify

$11r\le \:-6$

Divide both sides by 11

$\frac{11r}{11}\le \frac{-6}{11}$

Simplify

$r\le \:-\frac{6}{11}$

Therefore, the solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

7 0

2 years ago

Find the distance between points S(6,−3)

Gelneren [198K]

Answer:

.....................

4 0

3 years ago

May someone help me with this problem?

Katyanochek1 [597]

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

Step-by-step explanation:

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\$

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

7 0

2 years ago