Question

May someone help me with this problem?

Answer 1

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} }$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } }$

Step-by-step explanation:

a.

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} }$

b.

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } }$