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Evgen [1.6K]
3 years ago
5

Can someone please help me i literally am soo confused

Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:

a. Between 6.7 and 6.9

Step-by-step explanation:

√(25 + 3 + 17) = √45

6² = 36

7² = 49

√45 is close to 7 but slightly under.  So best answer is A.

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Fittoniya [83]
Yeah what about it ???
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3 years ago
Steps of sloving system of equation steps
MariettaO [177]

Answer:

Step-by-step explanation:

Solve 1 equation for 1 variable. ( Put in y = or x = form)

Substitute this expression into the other equation and solve for the missing variable.

Substitute your answer into the first equation and solve.

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6 0
3 years ago
The local skating rink pays Mary a fixed rate per pupil plus a base amount to work as a skating instructor. She earns $90 for
baherus [9]

Answer:The expressions for the payment made to Mary are,

        (Monday)      90 = 15m + b

        (Tuesday)     62 = 8m + b

where m and b are the fee per student and the base fee, respectively. Solving for m and b, the values are 4 and 30.

The equation that represents Mary's earning is

                                   y = 4x + 30

For 20 students,

                                   y = 4(20) + 30 = 110

For Lisa's earnings,

                                    y = 8x + 15

Substituting 20,

                                   y  =8(20) + 15 = 175

Thus, Lisa would earn more than Mary by $65.

Read more on Brainly.com - brainly.com/question/1560980#readmore

Step-by-step explanation:

5 0
3 years ago
The given line segment has a midpoint at (3, 1).
Katena32 [7]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through (x_1,y_1)\ and\ (x_2,y_2) is:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}.

Therefore the line passing through (2, 4) and (4, -2) has an equation:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

m_1m_2=-1.

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}

Since it is the  perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is y=\frac{1}{3}x

7 0
3 years ago
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