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Finger [1]
3 years ago
15

What is 1 5/6 + 7 3/4=

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0

Answer: 9 7/12


TO simplify the answer make common denominator which would be 12 so 5/6 times 2 on each 10/12 & 3/4 x3 becomes 9/12 so those make 1 7/12 add with 1 and 7

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Elvaluate the expression.<br>9!/3!<br>a) 3<br>b) 6<br>c) 60,480<br>d) 362,874​
HACTEHA [7]

Answer:

c) 60,480

Step-by-step explanation:

9×8×7×6×5×4×3×2×1

÷

3×2×1

Cancel same numbers in the numerator and denominator.

So you're going to have= 9×8×7×6×5×4 divided by 1

Which gives you, 60,480.

Hope this helped:) Mark me brainiest please.

4 0
3 years ago
Find the circumference and area of a circle with a diameter of 22 inches. Leave your answers in terms of pi. (4 points) C = 11π;
Iteru [2.4K]

Answer:

C = 22π; A = 121π.

Step-by-step explanation:

To find the circumference of a circle, you do pi times the diameter. That would be 22pi.

To find the area of a circle, you do pi * r^2. The radius is the diameter divided by 2. That is 22 / 2, which is 11. Then, the area would be pi * 11^2 = pi * 121 = 121pi.

So, C = 22pi; A = 121pi.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Express this equation in logarithmic form. y = 10^x<br><br> x = ?
Lana71 [14]

From definition we have:

$x=\log_{10}y

8 0
3 years ago
the set points (-4,1),(-4,-4),(2,-4),(2,1) identifies the vertices of a quadrilateral which is the most specific description of
raketka [301]

Answer:

The answer is a trapezoid.

Hope this helped!


6 0
3 years ago
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In the 2000 Sydney Olympics, a special program initiated by IOC president Juan Antonio Samaranch allowed developing countries to
jok3333 [9.3K]

Answer:

The means for times for the first round of the 100 meter men’s swim is 52.64789 seconds

The satandar deviation for times for the first round of the 100 meter men’s swim is 7.60182 seconds

Step-by-step explanation:

The sample mean for a set of n data is given by:

\bar X = \frac{1}{n}\sum{x_i}

In other words, the sample mean of the times for 71 times of the first round measured in seconds is:

\bar X = \frac{1}{71}\sum{x_i} = 52.64789 seconds

The sample standard deviation for a set of n data is given by:

S = \sqrt{\frac{1}{n-1}\sum{(x_i - \bar x)^2}}

In other words, the sample standard deviation of the times for 71 times of the first round measured in seconds is:

S = \sqrt{\frac{1}{n-1}\sum{(x_i - \bar x)^2}} = 7.60182 seconds

8 0
3 years ago
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