Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
6(x+2)
you just factor 6 from the expression
hope this helps
Answer:
acute
Step-by-step explanation:q
Answer:
Ok:
Step-by-step explanation:
So f°g . means f(g(x)). (The ° should be more center and bigger but I don't know to do that on a keyboard). f(g(x)) means that you replace the x in f(x) with the g(x) function. i.e:
if f(x) = 2x+2
and g(x) = 
f(g(x)) =
.
Similarly, in this case, we get f(x) = 2x-3 and g(x) = 3x-2.
Then, f(g(x)) or f°g(x) is 2(3x-2) - 3.
And we plug in -2 to solve:
2(3(-2)-2)-3.
and get -19.
Check if I am wrong because everyone makes mistakes but that is the way to solve this.