Hello,
The key to doing these problems is writing the fraction for each event and multiplying them.
I will do the first problem for you.
First, you have to draw an ace. The chances of that are 4/52.
Then, you have to draw a jack. The chances of that are 4/51.
We changed 52 to 51, because we didn't replace the ace that we drew the first time.
Multiplying those fractions gives us the answer 4/663.
I hope this gets you started in the right directions,
MrEQ
<span>2x-y = -4 OR y = 2x+4
-3x+y=44
-3x + (2x+4)= 44
-x = 40
x = -40 and y = -76 (2*-40 + 4)
c-5d=2 OR c = 5d + 2
2c + d =4
2(5d+2) + d = 4
11d = 0
d = 0 and c = 2 </span>
The answer is six equal sized links because two, three, and six, are all factors of six.
Answer:
Step-by-step explanation:
<h3>Given</h3>
- f(x) = 3x-2 and g(x) = 2x+1
<h3>To find </h3>
<h3>Solution</h3>
- (f+g)(x) =
- f(x) + g(x) =
- 3x - 2 + 2x + 1 =
- 5x - 1
