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tester [92]
4 years ago
8

Graph the function y=1/2sin(x-pi/4)

Mathematics
1 answer:
wlad13 [49]4 years ago
6 0
y=\frac{1}{2}sin(x-\frac{\pi}{4})\\\\y=\frac{1}{2}sin(x)\\\\\Downarrow T_{\vec{a}=[\frac{\pi}{4};\ 0]}\\\\y=\frac{1}{2}sin(x-\frac{\pi}{4})

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I WILL GIVE BRAINLIEST<br> Evaluate the following expression.<br> 4 - (3 - 2)²
Tanya [424]

Answer:

3

Step-by-step explanation:

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7 0
4 years ago
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Please help !!!<br> I can’t solve this <br> The teacher doesn’t teach well
Scorpion4ik [409]

So here are 4 rules when it comes to exponents:

  1. When you raise a power to a power, you really just multiply the exponents: (x^m)^n=x^{m*n}
  2. When you multiply 2 exponents of the same base, you add the exponents together: x^m*x^n=x^{m+n}
  3. When you divide 2 exponents of the same base, you subtract the exponents: \frac{x^m}{x^n}=x^{m-n}
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<u>Part A:</u>

\frac{2x^3y^3}{4y^2}=\frac{1}{2}x^{3-0}y^{3-2}=\frac{1}{2}x^3y

<u>Part B:</u>

(\frac{x^{-8}}{y^{11}})^{-2}=\frac{x^{-8*-2}}{y^{11*-2}}=\frac{x^{16}}{y^{-22}}=\frac{x^{16}y^{22}}{1}=x^{16}y^{22}

<u>Part C:</u>

\frac{(2x^3)(x^4)^2}{8x^{11}}=\frac{(2x^3)(x^{4*2})}{8x^{11}}=\frac{(2x^3)(x^8)}{8x^{11}}=\frac{2x^{3+8}}{8x^{11}}=\frac{2x^{11}}{8x^{11}}=\frac{1}{4}x^{11-11}=\frac{1}{4}x^0=\frac{1}{4}

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Answer:

Step-by-step explanation:

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A_c=482.81 rounded to the nearest tenth. I used 3.14 for pi.

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A_t=\frac{1}{2}bh where h is the height of 12.4 and the base is the diameter which is 12.4 * 2 = 24.8

A_t=\frac{1}{2}(24.8)(12.4) so

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482.81 - 153.76 = 329.05 mm²

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What could you do to change the volume of a gas
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<span>Greater pressure will decrease the volume. Less Pressure will increase the volume. </span>
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