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3 years ago

Please help right now!!

Mathematics

2 answers:

Oksana_A [137]3 years ago

8 0

i can’t see the question

coldgirl [10]3 years ago

6 0

There’s no question...

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823 rounded to the nearest ten

34kurt

It would be 820 because any number you have to round that ends in 4,3,2, or 1 will round down.

4 0

3 years ago

State whether or not each equation or situation represents direct variation.

laiz [17]

give me time will think and say

3 0

2 years ago

Read 2 more answers

The line segment determined by A(4,7) and B(2, 9) along <0, –2>

Arlecino [84]

The endpoints of the image are $A'(x,y) = (4,5)$ and $B'(x,y) = (2,7)$ , respectively.

Note - The statement is incomplete. Complete description is shown below:

The line segment determined by $A(4,7)$ and $B(2,9)$ is translated along $\langle 0, -2\rangle$ . Determine the endpoints of the image of the line segment AB.

Vectorially speaking, the translation of a point is defined by this formula:

$P'(x,y) = P(x,y) + T(x,y)$ (1)

Where:

$P(x,y)$ - Original point.
$P'(x,y)$ - Resulting point.
$T(x,y)$ - Translation.

Now we proceed to calculate the endpoints of the image:

Point A

$A'(x,y) = A(x,y) + T(x,y)$

$A'(x,y) = (4,7) + (0,-2)$

$A'(x,y) = (4,5)$

Point B

$B'(x,y) = B(x,y) + T(x,y)$

$B'(x,y) = (2,9) + (0,-2)$

$B'(x,y) = (2,7)$

The endpoints of the image are $A'(x,y) = (4,5)$ and $B'(x,y) = (2,7)$ , respectively.

We kindly invite to see this question on translations: brainly.com/question/12463306

4 0

1 year ago

Please help me answer this

prohojiy [21]

9514 1404 393

Answer:

z^11

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)(a^c) = a^(b+c)

$z^5\cdot z^6=z^{5+6}=\boxed{z^{11}}$

Additional comment

It might help you to think of an exponent as indicating repeated multiplication. It tells you how many times the factor is repeated. In this case, it means ...

$z^5\cdot z^6=(z\cdot z\cdot z\cdot z\cdot z)\cdot(z\cdot z\cdot z\cdot z\cdot z\cdot z)\\=z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z = z^{11}$