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3 years ago

given the equation y-5=5x determine whether the points (2,12) and (-2,-5) are a solution on the graph

1 answer:

6 0

(x,y)
sub points to see if we get true statemtn

(2,12)
x=2 and y=12

12-5=5(2)
7=10
false
no, (2,12) is not a point

(-2,-5)
x=-2
y=-5

-5-5=5(-2)
-10=-10
true
(-2,-5) is a soltuion

(-2,-5) is the only solution given that works

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D is correct answer

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2 years ago

15. Rewrite the given functions in

Lisa [10]

15. The vertex form of f(x) = x² + 8x - 10 is f(x) = (x + 4)² - 26

17. The standard form of g(x) = (x + 3)² - 4 is g(x) = x² + 6x + 5

Step-by-step explanation:

Any quadratic function has:

1. A vertex form form f(x) = a(x - h)² + k, where (h , k) are the

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2. A standard form g(x) = ax² + bx + c, where a , b , c are constant and

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3. the x-coordinate of the vertex point h = $\frac{-b}{2a}$ and

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15.

∵ f(x) = x² + 8x - 10

∴ a = 1 and b = 8

∵ h = $\frac{-b}{2a}$

∴ h = $\frac{-8}{2(1)}=-4$

∴ h = -4

∵ k = f(h)

∴ k = f(-4)

- Substitute x by -4 in f(x)

∴ k = (-4)² + 8(-4) - 10

∴ k = 16 - 32 - 10

∴ k = -26

∴ f(x) = (x - -4)² + (-26)

∴ f(x) = (x + 4)² - 26

The vertex form of f(x) = x² + 8x - 10 is f(x) = (x + 4)² - 26

17.

∵ g(x) = (x + 3)² - 4

- Lets solve the power 2 of the bracket:

(1st + 2nd)² = (1st)(1st) + 2(1st)(2nd) + (2nd)(2nd)

∵ (x + 3)² = (x)(x) + 2(x)(3) + (3)(3)

∴ (x + 3)² = x² + 6x + 9

∴ (x + 3)² - 4 = (x² + 6x + 9) - 4

∵ 9 - 4 = 5

∴ (x + 3)² - 4 = x² + 6x + 5

The standard form of g(x) = (x + 3)² - 4 is g(x) = x² + 6x + 5

Learn more:

You can learn more about the vertex form of quadratic function in brainly.com/question/9390381

#LearnwithBrainly

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3 years ago

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Marina86 [1]

Answer:

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Step-by-step explanation:

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