given the equation y-5=5x determine whether the points (2,12) and (-2,-5) are a solution on the graph

Simplify x to the 1/3 power (x to the 1/2 power + 2x to the 2 power )

OverLord2011 [107]

Answer:

x^(5/6) + 4(x^(7/3))

Step-by-step explanation:

Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )

Simplify x^(1/3) × (x^(1/2) + (2x)^2)

= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)

= x^(1/3+1/2) + 4(x^(1/3+2))

= x^(5/6) + 4(x^(7/3))

x^(1/3) is y such that y^3 = x

(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x

x^(1/2) = √2 = y such that y^2 = x

(2x)^2 = 4x^2

6 0

3 years ago

Easy Question! 5pts + branliest for the correct answer!

Advocard [28]

Answer:

29

Step-by-step explanation:

For the two digit numbers it has to end in a zero or five and be greater than 9 and below 100.

There are 18 multiples of 5 that are 2 digit

For multiples of 7... it's easier to write it out because the total number will will less than 20.

There are 13 multiples of 7 that are 2 digits

Now you have to subtract the multiples of 7 that end in a 0 or 5

That give you 11 multiples

Add 11 and 18 to get 29

5 0

3 years ago

Read 2 more answers

Can you help me please?

skad [1K]

Answer:

U= 53-degrees because of the definition of a straight angle

V=74-degrees

Step-by-step explanation:

5 0

3 years ago

Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d

Alexxx [7]

Answer:

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

$p_v =P(\chi^2$

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=35$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s =2.12$ represent the sample deviation obtained

$\sigma_0 =3$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 9$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

6 0

3 years ago

HELP ME PLEASEE faiuurhdkdgkgd

inysia [295]

Answer:

Option b is the right answer.

5 0

3 years ago