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3 years ago

Ik the answer I just want make sure I’m correct

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

7 0

Answer:

3,0

Step-by-step explanation:

svp [43]3 years ago

7 0

the slope is 1/2 and the y intercept is 3

hope this helps!! <3

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If veronica reed is paid a gross weekly salary of $1036.00, what is her gross annual salary?

Ber [7]

So, (weekly) she receives 1036.00.
The question is asking to find out the (annual) salary which is a year.
There are about 52 weeks in a year.
To find the amount being payed annually we multiply 1036 by 52
=53,872.

3 0

4 years ago

AEFG is located at E (0,0), F (-7, 4), and G (0,8). Which statement correctly classifies AEFG?

viva [34]

Answer:

ΔEFG is an isosceles triangle

Step-by-step explanation:

8 0

3 years ago

Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"

vampirchik [111]

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h$

Employ a standard trick used in proving the chain rule:

$\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h$

The limit of a product is the product of limits, i.e. we can write

$\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)$

The rightmost limit is an exercise in differentiating $\sqrt x$ using the definition, which you probably already know is $\dfrac1{2\sqrt x}$ .

For the leftmost limit, we make a substitution $y=\sqrt x$ . Now, if we make a slight change to $x$ by adding a small number $h$ , this propagates a similar small change in $y$ that we'll call $h'$ , so that we can set $y+h'=\sqrt{x+h}$ . Then as $h\to0$ , we see that it's also the case that $h'\to0$ (since we fix $y=\sqrt x$ ). So we can write the remaining limit as

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}$

which in turn is the derivative of $\tan y$ , another limit you probably already know how to compute. We'd end up with $\sec^2y$ , or $\sec^2\sqrt x$ .

So we find that

$\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}$

7 0

4 years ago

Write two expressions for the perimeter of a square. Explain what information is in

Gnoma [55]

Two expressions for the perimeter of a square are:
4a
- a represents one side of the square
a + a + a + a
- a representa one side of the square

the first expression does not include any addition. But the two expressions are actually equivalent.

3 0

2 years ago

Which expression represents this word phrase? eight less than the quotient of x and 3 x−83 8−x3 x3−8 3x−8

lozanna [386]

Quotient is basically the answer produced when dividing two numbers.

For example, the quotient of 6 and 3 is 2 because when I divide 6 by 3, I get 2.

Eight less than the quotient of x and 3 = $\frac{x}{3} - 8$

3 0

3 years ago

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