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3 years ago

A basketball hoop witha circumference of 56.52 inches i need to find the diameter

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

5 0

Answer:

Exactly, It would be this: 8.99543738355 . But rounded is 9 or 8.99

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saul85 [17]

Answer:

1 7/12 cups

Step-by-step explanation:

1/2 x 3 1/6 = 1/2 x 19/6 = 19/12 or 1 7/12

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3 years ago

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Please answer 7/10k=21 find x ill give you brainliest

algol [13]

Answer:

k=2.1

Step-by-step explanation:

7/10k=21

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10k=21

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3 years ago

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3 years ago

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VladimirAG [237]

Answer:

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Step-by-step explanation:

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3 years ago

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Simplify the radical expression completely LaTeX: 3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}3 5 − 3 11 + 2 121 − 3 90 A. La

lora16 [44]

Answer:

$3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}$

Step-by-step explanation:

Given

$3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}$

Required

Simplify the expression

$3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}$

Express the square root of 121 as 11

$3\sqrt{5}\:-\:3\sqrt{11}+2 * 11-3\sqrt{90}$

$3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{90}$

Express 90 as 9 * 10

$3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9 * 10}$

Split the surd to 2

$3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9} * \sqrt10}$

Express the square root of 9 as 3

$3\sqrt{5}\:-\:3\sqrt{11}+22-3 * 3 * \sqrt10}$

$3\sqrt{5}\:-\:3\sqrt{11}+22-9 * \sqrt10}$

$3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}$

Hence, the result of the expression is

$3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}$

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3 years ago