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Stels [109]
2 years ago
10

14. What point is in the first quadrant? a. (1,-2) b. (-2.1) C (1,2) d. (-2,-1)

Mathematics
1 answer:
Viefleur [7K]2 years ago
4 0
Mf- we need a picture
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What r radicals????????
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3 years ago
Sarah had 16 stickers. Al gave her 25 more. How many stickers does Sarah have now?
Amiraneli [1.4K]

Answer:

Sarah had 16 stickers. Al gave her 25 more. How many stickers does Sarah have now? 41

Step-by-step explanation:

8 0
3 years ago
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If the point (a,3) lies on the graph of the equation 5x + y = 8 then a =?
Contact [7]

Answer:

a = 1

Step-by-step explanation:

Given the point (a, 3) is on the line: 5x + y = 8.

Any point on the line satisfies the equation.

So, (a, 3) should satisfy the equation 5x + y = 8

Substituting x = a and y = 3, we get:

5(a) + 3 = 8

$ \implies 5a = 5 $

⇒ a = 1

Therefore, (1, 3) is the point on the line.

3 0
3 years ago
PLease help me out with this...I will mark the first one as the brainiest answer.
Slav-nsk [51]
You cannot add row 2 to column 3 because they have different dimensions. You can do any of the other operations, but the only one that makes any sort of sense is ...
  Multiply row 2 by -1 and add it to row 3

_____
It makes no sense to multiply a row by zero. That makes the entire row zero and makes the matrix useless for finding any sort of solution.

You can switch columns, but that doesn't get you any closer to a solution here.

If I were trying to find a solution, I might
  switch rows 1 and 2
  multiply the new row 1 by -3 and add it to the new row 2
  multiply the new row 1 by 2 and add it to row 3
This sequence of operations will make the first column [1 0 0], reducing the problem to 2×2 from 3×3.
3 0
3 years ago
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Find the value of ×<br><img src="https://tex.z-dn.net/?f=3x%20%2B%202%28x%20-%204%29%20%3D%2014" id="TexFormula1" title="3x + 2(
sasho [114]

Answer:

x = 22/5

Step-by-step explanation:

3x+2(x-4) = 14

Distribute

3x+2x -8 = 14

5x - 8 = 14

Add 8 to each side

5x-8+8 = 14+8

5x = 22

Divide by 5

5x/5 = 22/5

x = 22/5

4 0
3 years ago
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