Given:
The equation of a circle is
A tangent line l to the circle touches the circle at point P(12,5).
To find:
The gradient of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is
Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is
We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.
Therefore, the gradient or slope of the tangent line l is 
.
Answer:
4 divided by one-sixth = 2
Step-by-step explanation:
Given 4fraction bars
If each fraction bars has 6boxes, then we can get the total boxes for 4fractiom bars as shown;
1 fraction bars = 6boxes
4fraction bars = x
Cross multiply
1 × x = 4×6
x = 4× 6/1
x = 4 ÷ 1/6
Hence the division problem that modelled the expression is 4 ÷ 1/6
4÷1/6 = 4×6/1
4÷1/6 = 24
Option A is correct
The number must be 0, because any other number would multiply to a different product.
You can name Plane P, many different ways,
Assuming you are asking this out of a textbook staring at a figure of a Parallelogram, their are probably points inside that shape and the way you would name it would be naming using any three points in the plane that are NOT on the same line in any order. <span />
