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zepelin [54]
3 years ago
9

NEED HELP ASAP, WILL GIVE BRAINLIEST

Mathematics
1 answer:
Scrat [10]3 years ago
4 0
D.........................
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If he is paid 3.27 for every widget assembled...and he assembles 209...then his total pay for the week is : 3.27 * 209 = $ 683.43 <==
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The endpoints of a line segment graphed on a Cartesian coordinate system are (4, 1) and (-2, -4). What are the coordinates of th
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The midpoint of (x1,y1) and (x2,y2) is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

just average them


(4,1) and (-2,4)
the midpoint is  (\frac{4-2}{2},\frac{1-4}{2})=(\frac{2}{2},\frac{-3}{2})=(1,-1.5)
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4 years ago
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If a bank account doubles in size every 5 years, then by what percent does it grow after only 3 years? Round to the nearest tent
mr Goodwill [35]

Answer:

Step-by-step explanation:

Alright, let get started.

Suppose the initial deposit in account = x

After five years, this accounts get doubled means  = 2x

Means in 5 years , the growth = 2x-x = x

So, in 1 year, the growth will be = \frac{x}{5}

So, in 3 years, the growth will be = \frac{x}{5}*3=\frac{3x}{5}

So percent grwoth will be = \frac{\frac{3x}{5}}{x}*100 = 60

Hence percentage growth is 60 %.    :  Answer

Hope it will help :)


4 0
3 years ago
Using either the integral, limit comparison, comparison, or p-test, determine if the series converges or diverges. ∑n=3→∞ <img s
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See below. The series converges.

Step-by-step explanation:

5 0
3 years ago
webassign If a snowball melts so that its surface area decreases at a rate of 6 cm2/min, find the rate at which the diameter dec
drek231 [11]

Answer:

The answer is \frac{3}{10\pi }  cm/min

Step-by-step explanation:

Assuming the snowball is a perfect sphere, then if A denotes the surface area and D the diameter then:

A=4\pi r^{2} = 4\pi (\frac{D}{2} )^{2} =\pi  D^{2}

Differentiating wrt r we have:

\frac{dA}{dD} =2\pi D

We are told that \frac{dA}{dt}= -6 and we want to find \frac{dD}{dt}

By the chain rule we have:

\frac{dA}{dD}=\frac{dA}{dt}.\frac{dt}{dD}=\frac{\frac{dA}{dt} }{\frac{dD}{dt} }

∴2\pi D=-\frac{6}{\frac{dD}{dt} }

∴\frac{dD}{dt}=-\frac{6}{2\pi D}

When D=10 then

\frac{dD}{dt} =-\frac{6}{10*2\pi } =-\frac{3}{10\pi }

The sign (-) shows that the D is decreasing.

3 0
3 years ago
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