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NISA [10]
3 years ago
12

In a regular polygon with n sides, what is the smallest angle of rotation about the center for which the polygon will be napped

onto itself?
A: n
B: n/360
C: 360/n
D: 180/n
Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer:

B

this is because circle has the sum total of 360 and the side of the polygon is n

n/360

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Researchers measured the percent body fat and the preferred amount of salt (percent weight/volume) for several children. Here ar
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Answer: b) τ = 0.3

Step-by-step explanation:

Given the data :

Amount of salt (x)____% body fat(y)

0.2 _______________20

0.3 _______________30

0.4 _______________22

0.5 _______________30

0.7 _______________38

0.9 _______________23

1.1 ________________30

The correlation Coefficient as obtained from the online pearson correlation Coefficient calculator is 0.3281 = 0.3 (to one decimal place) which implies that a weak positive correlation or relationship exists between the preferred amount of salt taken to the percentage body weight of an individual. This is because the value is positive and closer to 0 than 1. The closer the weaker the degree of correlation. With positive values implying a positive relationship (that is an increase in variable A leads to a corresponding increase in B and vice-versa).

4 0
3 years ago
A 1-liter bottle of orange juice used to cost $2.85 at a food market. Its price has increased; the new price is 110 percent of t
Mama L [17]

D. 3.14

hop this helps ^o^

3 0
3 years ago
Which is the solution of the following system? <br> x-y=11<br> -x+y=-11
aleksandrvk [35]

Answer: Infinite solutions. It is the same line

Step-by-step explanation:

7 0
3 years ago
How do you get horizontal asymptopes?
Nady [450]
<span>1) If the degree (the largest exponent) of the denominator is bigger than the degree of the numerator, the horizontal asymptote is the x-axis (y = 0).
<span>
2) If the degree of the numerator is bigger than the denominator, there is no horizontal asymptote.</span></span>
4 0
3 years ago
At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by –0.50t, in m/s^2 for t in seconds. By
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The car's velocity at time t is

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It comes to rest at

v(t)=0\implies16\dfrac{\rm m}{\rm s}=\left(0.25\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=8.0\,\mathrm s

Its velocity over this period is positive, so that the total distance the car travels is

\displaystyle\int_0^{8.0}v(t)\,\mathrm dt=\left(16\dfrac{\rm m}{\rm s}\right)(8.0\,\mathrm s)+\frac13\left(-0.25\dfrac{\rm m}{\mathrm s^2}\right)(8.0\,\mathrm s)^3=\boxed{85\,\mathrm m}

so the answer is D.

4 0
3 years ago
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