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laila [671]
3 years ago
9

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3,

16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)
Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

Option 3: (0,-9)

Step-by-step explanation:

Description of graphed function:

Minimum value of function = (0,-9)

Maximum values of function = (-2.3,16), (2.3,16)

Crosses the x-axis = (-3, 0), (-1, 0), (1, 0), and (3, 0)

Crosses the y-axis = (0, -9).

We need to find the y-intercept of the graphed function.

y-intercept is the point where the graph of a function intersect the y-axis.

From the given information it is clear that the graph of function intersect the y-axis at point (0,-9). So, the y-intercept of the function is at (0,-9).

Therefore, the correct option is 3.

nikitadnepr [17]3 years ago
5 0

Answer:

(0, -9)

Step-by-step explanation:

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)

The y-intercept is the point where x = 0, and It says there that the graph crosses the y-axis at (0, -9)

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Gre4nikov [31]

Answer:

a = (p - 3b)/10

Step-by-step explanation:

Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).

p = 10a + 3b

First, subtract 3b from both sides.

p (-3b) = 10a + 3b (-3b)

p - 3b = 10a

Next, isolate the a. Divide 10 from both sides.

(p - 3b)/10 = (10a)/10

(p - 3b)/10 = a

a = (p - 3b)/10 is your answer.

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4 years ago
Use the drop-down menus to complete the proof. by the unique line postulate, you can draw only one segment,
Doss [256]

The reflection of BC over I is shown below.

<h3>What is reflection?</h3>
  • A reflection is a mapping from a Euclidean space to itself that is an isometry with a hyperplane as a set of fixed points; this set is known as the reflection's axis (in dimension 2) or plane (in dimension 3).
  • A figure's mirror image in the axis or plane of reflection is its image by reflection.

See the attached figure for a better explanation:

1. By the unique line postulate, you can draw only one line segment: BC

  • Since only one line can be drawn between two distinct points.

2. Using the definition of reflection, reflect BC over l.

  • To find the line segment which reflects BC over l, we will use the definition of reflection.

3. By the definition of reflection, C is the image of itself and A is the image of B.

  • Definition of reflection says the figure about a line is transformed to form the mirror image.
  • Now, the CD is the perpendicular bisector of AB so A and B are equidistant from D forming a mirror image of each other.

4. Since reflections preserve length, AC = BC

  • In Reflection the figure is transformed to form a mirror image.
  • Hence the length will be preserved in case of reflection.

Therefore, the reflection of BC over I is shown.

Know more about reflection here:

brainly.com/question/1908648

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The question you are looking for is here:

C is a point on the perpendicular bisector, l, of AB. Prove: AC = BC Use the drop-down menus to complete the proof. By the unique line postulate, you can draw only one segment, Using the definition of, reflect BC over l. By the definition of reflection, C is the image of itself and is the image of B. Since reflections preserve , AC = BC.

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Step-by-step explanation:

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