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laila [671]
3 years ago
9

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3,

16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)
Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

Option 3: (0,-9)

Step-by-step explanation:

Description of graphed function:

Minimum value of function = (0,-9)

Maximum values of function = (-2.3,16), (2.3,16)

Crosses the x-axis = (-3, 0), (-1, 0), (1, 0), and (3, 0)

Crosses the y-axis = (0, -9).

We need to find the y-intercept of the graphed function.

y-intercept is the point where the graph of a function intersect the y-axis.

From the given information it is clear that the graph of function intersect the y-axis at point (0,-9). So, the y-intercept of the function is at (0,-9).

Therefore, the correct option is 3.

nikitadnepr [17]3 years ago
5 0

Answer:

(0, -9)

Step-by-step explanation:

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)

The y-intercept is the point where x = 0, and It says there that the graph crosses the y-axis at (0, -9)

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Answer:

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Step-by-step explanation:

Standard form of a polynomial:

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Example:

a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+......

Given,

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Step-by-step explanation:

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3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
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Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

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No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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Answer:

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Step-by-step explanation:

30+30=60

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