Question

Glen Davis is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 74\%74%74, percent of the time. What is the probability of Glen Davis making none of his next 4 free throw attempts?

Answer 1

Answer:

(1−0.74)  ^4

Step-by-step explanation:

Answer 2

Answer:

0.00457 or 0.457%

Step-by-step explanation:

Glen Davis makes a free throw 74% of the time, meaning he misses 26% of the time. Four him to miss four in a row, it would require him to miss his first throw and his second throw and his third throw and his fourth throw. I highlight and because it is a helpful tip to remember that AND situations require multiplication while OR situations require addition.

So in this question we multiply the probabilities of him missing.

$P(MMMM) = \frac{26}{100}* \frac{26}{100} *\frac{26}{100}* \frac{26}{100} = 0.00457$

This answer has been rounded off to three significant figures