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3 years ago

Lots of points 53 points is the √-4 considered a real number why or why not

Mathematics

2 answers:

evablogger [386]3 years ago

4 0

No. Negative Sqaure Roots are not real numbers

Illusion [34]3 years ago

4 0

Very interesting question!

But, √-4 is not a real number; in fact, the result of √-4 is 2i.

The i is an imaginary number and it basically is a solution for √-1

(So, i^2 is = -1).

Since -4 is negative, the square root doesn't exist (in terms of real numbers) just because you can't multiply any two identical numbers to get a negative result.

-2 x -2 = +4
2 x 2 = +4

That is why √-4 is NOT considered a real number.

Hope I could help you out!
Have a good one, and God bless!

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Correct answer get the BRAINLIEST ANSWER!

OLga [1]

Here is how I completed the problem:

I started by creating a ratio:

$\frac{x}{0.18} + \frac{360}{0.10} = \frac{x+360}{0.15}$

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From here, I solved for 'x':

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Read 2 more answers

4. Which of the following lines is perpendicular to y = -2X + 8?

Alenkinab [10]

For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1.

That is to say:

$m_ {1} * m_ {2} = - 1$

We have the following equation:

$y = -2x + 8$

So:

$m_ {1} = - 2$

Thus:

$m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {- 2}\\m = \frac {1}{2}$

Thus, a line perpendicular to the given line must have slope $m = \frac {1} {2}.$

Option A:

$x + 2y = 8\\2y = -x + 8\\y = - \frac {1} {2} x + 4$

It is not perpendicular!

Option B:

$x-2y = 6\\2y = x-6\\y = \frac {1} {2} x-3$

If it is perpendicular!

Option C:

$2x + y = 4\\y = -2x + 4$

It is not perpendicular!

Option D:

$2x-y = 1\\y = 2x-1$

It is not perpendicular!

The correct option is option B

ANswer:

Option B

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