Lots of points 53 points is the √-4 considered a real number why or why not

Mathematics

2 answers:

evablogger [386]2 years ago

4 0

No. Negative Sqaure Roots are not real numbers

Illusion [34]2 years ago

4 0

Very interesting question!

But, √-4 is not a real number; in fact, the result of √-4 is 2i.

The i is an imaginary number and it basically is a solution for √-1

(So, i^2 is = -1).

Since -4 is negative, the square root doesn't exist (in terms of real numbers) just because you can't multiply any two identical numbers to get a negative result.

-2 x -2 = +4
2 x 2 = +4

That is why √-4 is NOT considered a real number.

Hope I could help you out!
Have a good one, and God bless!

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Lostsunrise [7]

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3 years ago

which inequality represents all values of x for which the quotient below is defined?√8x^2 divided by √2x

MA_775_DIABLO [31]

Answer:

The function is defined when x > 0

Step-by-step explanation:

Functions with radicals are only undefined when the value in the radical is negative, because the root of a negative number is imaginary.

We know the function is undefined when the denominator is equal to zero. $\sqrt{2x}$ is equal to zero when x=0.

We also know that functions with radicals are undefined when the value in the radicals are negative, because the root of a negative number is imaginary. . $8x^{2}$ will always be positive, but $2x$ is negative when x < 0.