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Greeley [361]
4 years ago
15

Mr. Gomez paid a total of $267 for the repairs on his car. The cost of the labor was two thirds of the total charge. Find the ch

arge for labor
Mathematics
1 answer:
Mars2501 [29]4 years ago
5 0
Here is one way I learned from teacher take 267 and ÷ by 3 and there are three part and if you do it right you might have a left over so and take one of those three ÷ and see how much you have left and × it by 2
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What is the common ratio of the sequence?
Semenov [28]

Answer:

A -3

Step-by-step explanation:

-2 x -3 = 6

6 x -3 = -18

-18x -3 = 54

5 0
3 years ago
Sam had 11/2 m of rope. he cut off 5/8 m and used it for a project. how much rope does sam have left?
lakkis [162]
39/8 m or 4.875m is left
6 0
3 years ago
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and
masya89 [10]

Answer:

a) There is a 100% probability that the (sample) average time waiting in line for these customers is less than 10 minutes.

b) There is a 100% probability that the (sample) average time waiting in line for these customers is between 5 and 10 minutes.

c) There is a 0% probability that the (sample) average time waiting in line for these customers is less than 6 minutes.

d) Because there are less observations, it would be less accurate.

e) Because there are moreobservations, it would be more accurate.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. This means that \mu = 8.2, \sigma = 1.5.

Suppose that a random sample of n = 49 customers is observed

This means that s = \frac{1.5}{\sqrt{49}} = 0.21.

(a) Less than 10 minutes.

This probability is the pvalue of Z when X = 10. So:

Z = \frac{X - \mu}{s}

Z = \frac{10 - 8.2}{0.21}

Z = 8.57

Z = 8.57 has a pvalue of 1.

This means that there is a 100% probability that the (sample) average time waiting in line for these customers is less than 10 minutes.

(b) Between 5 and 10 minutes.

This probability is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 5.

From a), we have that the zscore of X = 10 has a pvalue of 1.

For X = 5.

Z = \frac{X - \mu}{s}

Z = \frac{5 - 8.2}{0.21}

Z = -15.24

Z = -15.24 has a pvalue of 0.

Subtracting, we have that there is a 100% probability that the (sample) average time waiting in line for these customers is between 5 and 10 minutes.

(c) Less than 6 minutes.

This probability is the pvalue of Z when X = 6. So:

Z = \frac{X - \mu}{s}

Z = \frac{6 - 8.2}{0.21}

Z = -10.48

Z = -10.48 has a pvalue of 0.

This means that there is a 0% probability that the (sample) average time waiting in line for these customers is less than 6 minutes.

(d) If you only had two observations instead of 49 observations, would you believe that your answers to parts (a), (b), and (c), are more accurate or less accurate? Why?

The less observations there are, the less acurrate our results are.

So, because there are less observations, it would be less accurate.

(e) If you had 1,000 observations instead of 49 observations, would you believe that your answers to parts (a), (b), and (c), are more accurate or less accurate? Why?

The more observations there are, the more acurrate our results are.

So, because there are moreobservations, it would be more accurate.

8 0
3 years ago
Harper knows he is 50 yards from the school. The map on his phone shows that the school is 3/4 inch from his current location. I
prisoha [69]

Answer:

150 yards

Step-by-step explanation:

50 yards=3/4inch

xyards=3inches

50/4=12.5

4*3=12

12.5*12=150

150 yards

7 0
3 years ago
7,920 yd = how many mi ??
Arturiano [62]
The answer is 4.5 miles
8 0
3 years ago
Read 2 more answers
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