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Juliette [100K]
3 years ago
9

Go the Deethe pernotesfied16САof​

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0

Answer: It is gvgtyhf

Step-by-step explanation:

tankabanditka [31]3 years ago
3 0

Answer:

WHAT IS THE COMPLETE QUESTION⁉️

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A line with a slope of 1/2 passes through the point (2, -1) what is the Equation of the line​
Sonja [21]

Answer:

y=1/2x-2

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
How can the bar symbol be used to show the quotient of 7÷11 if the division is carried on forever?
Thepotemich [5.8K]

\bf 7\div 11\implies 0.636363636363636........\implies 0.\overline{63}

4 0
3 years ago
A walking path across a park is represented by the equation y=-3x - 3.A
kifflom [539]

Answer:

  y -6 = 1/3(x +3)   or   y = 1/3x +7

Step-by-step explanation:

The slope of the line describing the given path is the x-coefficient, -3. The slope of the perpendicular line will be the negative reciprocal of that:

  m = -1/(-3) = 1/3

The point-slope form of the equation for a line can be used to write the equation for the new path:

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

For m=1/3 and (h, k) = (-3, 6), the new path can be represented by ...

  y -6 = 1/3(x +3) . . . . point-slope form

  y = (1/3)x +7 . . . . . . slope-intercept form

5 0
3 years ago
Write a system of inequalities using the given graph
ziro4ka [17]

For dark line

  • (0,1)
  • (-1,-4)

Slope

  • m=-4-1/-1=5

Equation in point slope form

  • y-1=5x
  • y=5x+1

Put (0,0)

  • 0<1

As line is dark sign is ≤

The inequality

  • y≤5x+1

For dashed line

  • (2,0)
  • (0,-2)

Equation in intercept form

  • x/2-y/2=1
  • x-y=2
  • y=x-2

Put (0,0)

  • 0>-2

Symbol is >

Inequality is

  • y>x-2
7 0
2 years ago
Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
3 years ago
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