Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Answer:
1 rubber cube dude give since we'll
X=2/3y-4
EXPLANATION
3x-2y=-12
You take -2y to the other side
It becomes 3x=2y-12
Then you divide 3
X=2/3y
-12/3=-4
X=2/3y-4
Answer:
SA = 76 yd²
Step-by-step explanation:
Use the formula given:
- SA = 2(4)(2) + 2(4)(5) + 2(2)(5)
- SA = 16 + 40 + 20
- SA = 76
The units are yards²
SA = 76yd²
-Chetan K
5.1% =5.1/100=0.051
Therefore Multiplying 0.051 x 90
This gives 4.59