Answer:
Step-by-step explanation:
Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42
Let X be the no of passengers who report
X is N(132, 42)
Or Z is 
a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.
the probability that the demand will exceed the capacity of this airplane
=
b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers
=
=0.4474+0.3907
=0.8381
c) the probability that the demand for this flight will be less than 100 passengers
d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers
=
e) 79th percentile of this distribution
=
834 ➗ 2 =417. I hope I helped :)
Step-by-step explanation:
a triangular number n is the sum of all natural numbers <= n.
t1 = 1
t2 = 1+2 = 3
t3 = 1+2+3 = 6
t4 = 1+2+3+4 = 10
...
so,
tn = tn-1 + n
47.
1×8 + 1 = 9 is a square number.
3×8 + 1 = 25 is a square number
6×8 + 1 = 49 is a square number
10×8 + 1 = 81 is a square number
48.
1/3 = 0 remainder 1
3/3 = 1 remainder 0
6/3 = 2 remainder 0
10/3 = 3 remainder 1
15/3 = 5 remainder 0
21/3 = 7 remainder 0
28/3 = 9 remainder 1
so, there seems to be a pattern 1 0 0 1 0 0 1 0 0 1 ...
49.
1/4 = 0 remainder 1
4/4 = 1 remainder 0
9/4 = 2 remainder 1
16/4 = 4 remainder 0
25/4 = 6 remainder 1
36/4 = 9 remainder 0
49/4 = 12 remainder 1
so, there seems to be a pattern 1 0 1 0 1 0 1 0 1 0 1 ...
50.
polygonal numbers is the real name for this.
the formula for dimensions = 5 is
(3n² − n)/2
for dimensions = 6 it is
2n² - n
so, dimensions=5 (and therefore dividing also by 5) we get the remainders
1/5 = 0 remainder 1
5/5 = 1 remainder 0
12/5 = 2 remainder 2
22/5 = 4 remainder 2
35/5 = 7 remainder 0
51/5 = 10 remainder 1
70/5 = 14 remainder 0
92/5 = 18 remainder 2
117/5 = 23 remainder 2
145/5 = 29 remainder 0
here the pattern is 1 0 2 2 0 1 0 2 2 0 1 0 2 2 0 ...
dimensions=6 (and therefore dividing also by 6) we get the remainders
1/6 = 0 remainder 1
6/6 = 1 remainder 0
15/6 = 2 remainder 3
28/6 = 4 remainder 4
45/6 = 7 remainder 3
66/6 = 11 remainder 0
91/6 = 15 remainder 1
120/6 = 20 remainder 0
153/6 = 25 remainder 3
190/6 = 31 remainder 4
231/6 = 38 remainder 3
276/6 = 46 remainder 0
325/6 = 54 remainder 1
here the pattern is 1 0 3 4 3 0 1 0 3 4 3 0 1 0 3 4 3 0 ...
3,100 mg is 3.1 grams as there a 1000 mg in a gram.
Answer: Step 1: Reverse the signs of 
expression.
Step 2: Removing parenthesis
Step 3: Grouping like terms
Step 4: Combing like terms
Step 5: Writing the final expression in standard form
Step-by-step explanation: First expression :
Second expression : 
.
We need to subtract from .
Step 1: Reverse the signs of expression.
Step 2: Removing parenthesis
Step 3: Grouping like terms
![[-3x^3) + (-6x^3)] + [4x + 2x] + [(-7) + (-3)] + [5x^2]](https://tex.z-dn.net/?f=%5B-3x%5E3%29%20%2B%20%28-6x%5E3%29%5D%20%2B%20%5B4x%20%2B%202x%5D%20%2B%20%5B%28-7%29%20%2B%20%28-3%29%5D%20%2B%20%5B5x%5E2%5D)
Step 4: Combing like terms
Step 5: Writing the final expression in standard form
