Answer:
- #include <stdio.h>
-
- bool IsArrayEven(int inputVals[], int numVals){
- int i;
- for(i = 1; i < numVals; i++){
- if(inputVals[i] % 2 != 0){
- return false;
- }
- }
- return true;
- }
-
- bool IsArrayOdd(int inputVals[], int numVals){
- int i;
- for(i = 1; i < numVals; i++){
- if(inputVals[i] % 2 == 0){
- return false;
- }
- }
- return true;
- }
-
- int main()
- {
- int my_input[] = {5, 2, 4, 6, 8, 10};
-
- if(IsArrayEven(my_input)){
- printf("all even");
- }else if(IsArrayOdd(my_input)){
- printf("all odd");
- }else{
- print("not even or odd");
- }
- }
Explanation:
Firstly, write two functions to check if the input array is all even or all odd (Line 3-22). The key idea is to use modulus operator to check if a number % 2 equal to 0, it is an even number, if not, it is an odd. So long as one of the number is odd in the isArrayEven function, the function shall return false (Line 7). If no odd value detected, it return true (Line 11). The similar code logic is applied to isArrayOdd function too.
Then, we can call the two functions sequentially in the main program. If isArrayEven function return true, it display all even message (Line 28-29). If odd, display all odd (Line 30 -31). If neither, display not even or odd (Line 32-33).
Answer:
trade association
Explanation:
A trade association or industry trade group, business association, sector association or industry body is an organization founded by companies in a sector, this organization participates in public relationships like donations, but the main task is to do a collaboration between companies, even this organization participates politics relationships.
Answer:
Option C (DMCA) would be the correct choice.
Explanation:
- DMCA is designed to govern electronic channels and tackle the problems the online revolution confronts regarding copyright.
- DMCA's mission seems to be to accommodate the rights of intellectual property producers and investors and investigate anything other than a copyrighted material that really occurs throughout the digital environment.
The other given choice are not related to the given content. So that option C is the right one.
Answer:
A-attracting users who would find value in your website
Explanation:
:) hope this helps!!!!
Maybe right on why u think u will strive or how you will but i'm not sure