The digital revolution has affected a. almost all areas of movie-making, except makeup and hairstyling. b. only a small number o
1 answer:
You might be interested in
#include<iostream>
#include <fstream>
#include <vector>
#include <string>
#include "StatePair.h"
using namespace std;
int main() {
ifstream inFS;
int zip;
int population;
string abbrev;
string state;
unsigned int i;
vector<StatePair <int, string>> zipCodeState;
vector<StatePair<string, string>> abbrevState;
vector<StatePair<string, int>> statePopulation;
inFS.open("zip_code_state.txt");
if (!inFS.is_open()) {
cout << "Could not open file zip_code_state.txt." << endl;
return 1;
}
while (!inFS.eof()) {
StatePair <int, string> temp;
inFS >> zip;
if (!inFS.fail()) {
temp.SetKey(zip);
}
inFS >> abbrev;
if (!inFS.fail()) {
temp.SetValue(abbrev);
}
zipCodeState.push_back(temp);
}
inFS.close();
inFS.open("abbreviation_state.txt");
if (!inFS.is_open()) {
cout << "Could not open file abbreviation_state.txt." << endl;
return 1;
}
while (!inFS.eof()) {
StatePair <string, string> temp;
inFS >> abbrev;
if (!inFS.fail()) {
temp.SetKey(abbrev);
}
getline(inFS, state);
getline(inFS, state);
state = state.substr(0, state.size()-1);
if (!inFS.fail()) {
temp.SetValue(state);
}
abbrevState.push_back(temp);
}
inFS.close();
inFS.open("state_population.txt");
if (!inFS.is_open()) {
cout << "Could not open file state_population.txt." << endl;
return 1;
}
while (!inFS.eof()) {
StatePair <string, int> temp;
getline(inFS, state);
state = state.substr(0, state.size()-1);
if (!inFS.fail()) {
temp.SetKey(state);
}
inFS >> population;
if (!inFS.fail()) {
temp.SetValue(population);
}
getline(inFS, state);
statePopulation.push_back(temp);
}
inFS.close();
cin >> zip;
for (i = 0; i < zipCodeState.size(); ++i) {
}
for (i = 0; i < abbrevState.size(); ++i) {
}
for (i = 0; i < statePopulation.size(); ++i) {
}
}
Statepair.h
#ifndef STATEPAIR
#define STATEPAIR
#include <iostream>
using namespace std;
template<typename T1, typename T2>
class StatePair {
private:
T1 key;
T2 value;
public:
StatePair()
{}
void SetKey(T1 key)
{
this->key = key;
}
void SetValue(T2 value)
{
this->value = value;
}
T1 GetKey() { return key;}
T2 GetValue() { return value;}
void PrintInfo()
{
cout<<key<<" : "<<value<<endl;
}
};
Answer:
The following are the program to the given question:
import java.util.*;//import package for user input
public class Make //define class Make
{
public static void main(String[] ask) //define a main method
{
Scanner obx = new Scanner(System.in); //declare the Scanner class object
int size=obx.nextInt(); //get the size of the array from the user
int a[]=new int[size]; //declare an integer array with given size
String word[]=new String[size]; //declare a string array with given size
for(int i=0;i<size;i++) //set the for loop
word[i]=obx.next(); //get string input from the user
for(int i=0;i<size;i++) //iterates with the array, increase the count
{
for(int j=0;j<size;j++) //defining a loop to check value
{
if(word[i].equals(word[j])) //use if to check that elements of words
a[i]++;//increamenting array size
}
}
System.out.print("\n"); //use print for break line
for(int i=0;i<size;i++)//set for loop to print the following result
System.out.println(word[i]+" "+a[i]);//print value
}
}
Output:
Please find the attachment file.
Explanation:
- First, establish the predefined package required and instead define the main class and define the main method within the class and method.
- Declare the scanner class object and receive an object size in the 'size' variable thru the array.
- Next create two arrays, the integer type "a" with both the input size given and the string type "word" with the input size supplied.
- Define the loop for which string array elements are acquired and set two to again for loop, which increases with loop iteration the integer data type array by one.
- Lastly, set the loop for which this result is printed.
