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Maru [420]
2 years ago
15

A. X= 49/3 B. X= 21 C. X= 51 D. X= 9

Mathematics
1 answer:
Valentin [98]2 years ago
5 0
C- X=19 so I think it’s the correct answer if not I’m sorry:(
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Ms.Erma's oatmeal recipes calls for 2/5 of a cup of raisins.How many batches of cookies can she make if she has 4/5 cup of raisi
Tanya [424]

2 batches because 4/2 =2

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3 years ago
What are four consecutive odd integers that equals 184
Serggg [28]

1st: 2x-3  2nd: 2x-1 3rd: 2x+1 4th: 2x+3

adding the above you get 8x=184

3 0
3 years ago
Rhonda has $13. She has one $5 bill, three $1 bills, and one other bill. Is a other bill a $1 bill or a $5 bill explain
morpeh [17]

Answer:

$5 bill

Step-by-step explanation:

If Rhonda has $13 and she has a $5 bill and 3 $1 bills, then she has

5 + 3(1) + x = 13

5 + 3 + x = 13

8 + x = 13

x = 5.

The last bill must be a $5 bill to equal the remaining $5.

8 0
2 years ago
Mae Ling earns a weekly salary of 400 plus a 7% commission sales in a gift shop. How much would she make in a work week if she s
11111nata11111 [884]
Im pretty sure its 4,771 but id double check with a calculator

7 0
3 years ago
Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0
fomenos

• The value of the discriminant ,D= -16

,

• The solution to the quadratic equation is

x=\frac{1+2i}{5}\text{     or    }\frac{1-2i}{5}

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

,

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}

Note that:

√-1 = i

x=\frac{2\pm\sqrt[]{16\times-1}}{10}

x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}x=\frac{2\pm4i}{10}x=\frac{2}{10}\pm\frac{4i}{10}x=\frac{1}{5}\pm\frac{2}{5}ix=\frac{1\pm2i}{5}

That is;

\text{Either x=}\frac{1+2i}{5}\text{ or     x=}\frac{1-2i}{5}

7 0
1 year ago
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