Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
Answer:
the answer is x=3
Step-by-step explanation:
-3x=1-7
-3x=-6
-x=-6+3
-x=-3
x=3
21 because you turn the 5 yards in to feet which is 15, then you add 15+4+2=21
P = principal (initial amount), r = rate of interest, and t = time
So, A = 3000(1+0.025)^4
Answer: $3,311.44 (approximately)
We have to consider the Order of Operations
And Divide the question into different parts
So we first do the Exponent:
= 32
(3×32-26)=(96-26)=70
Solve the parts in parenthesis
(8-(4-9)=(8-(-5)=(8+5)=13 (minus and minus becomes addition)
Distribute 7
7(13)=91
Now put the equation and equate everything
(3×
+13(-2))+7(8-(4-9)=70+91=161
Final Answer=
161
