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3 years ago

8

1. Cooking oil is sold in two sizes of cans.

1 answer:

iren2701 [21]3 years ago

4 0

Answer:

Small can

Step-by-step explanation:

Price per liter for Small can = 2.20 /4 = 0.55

Price per liter for Large can = 3.24 / 6 = 0.54

0.55>0.54

small can > large can

I hope im right!!!

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Determine of which lines, if any, are parallel or perpendicular. Explain.

nalin [4]

Answer:

lines b and c are perpendicular

Step-by-step explanation:

Use slope

slope for parallel is the same

slope for perpendicular is negative reciprocal

line a slope- 1-3/-2-0 is -2/-2 or 1

line b slope- 1-4/4-6 is -3/-2 or 3/2

line c slope- 3-1/1-4 is 2/-3 or - 2/3

none are the same so none are parallel

- 2/3 is the negative reciprocal of 3/2 so lines b and c are perpendicular

8 0

2 years ago

Express 10500 in terms of its prime factors

8_murik_8 [283]

Step-by-step explanation:

$10500 = 3 \times 5 \times 5 \times 5 \times 7 \times 2 \times 2 \\ \\ 10500 = 2 \times 2 \times 3 \times 5 \times 5 \times 5 \times 7 \\ 10500 = {2}^{2} \times 3 \times {5}^{3} \times 7$

7 0

2 years ago

Based on the number of voids, a ferrite slab is classified as either high, medium, or low. Historically, 5% of the slabs are cla

AnnyKZ [126]

Answer:

(a) Name: Multinomial distribution

Parameters: $p_1 = 5\%$ $p_2 = 85\%$ $p_3 = 10\%$ $n = 20$

(b) Range: $\{(x,y,z)| x + y + z=20\}$

(c) Name: Binomial distribution

Parameters: $p_1 = 5\%$ $n = 20$

$(d)\ E(x) = 1$ $Var(x) = 0.95$

$(e)\ P(X = 1, Y = 17, Z = 3) = 0$

$(f)\ P(X \le 1, Y = 17, Z = 3) =0.07195$

$(g)\ P(X \le 1) = 0.7359$

$(h)\ E(Y) = 17$

Step-by-step explanation:

Given

$p_1 = 5\%$

$p_2 = 85\%$

$p_3 = 10\%$

$n = 20$

$X \to$ High Slabs

$Y \to$ Medium Slabs

$Z \to$ Low Slabs

Solving (a): Names and values of joint pdf of X, Y and Z

Given that:

$X \to$ Number of voids considered as high slabs

$Y \to$ Number of voids considered as medium slabs

$Z \to$ Number of voids considered as low slabs

Since the variables are more than 2 (2 means binomial), then the name is multinomial distribution

The parameters are:

$p_1 = 5\%$ $p_2 = 85\%$ $p_3 = 10\%$ $n = 20$

And the mass function is:

$f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z$

Solving (b): The range of the joint pdf of X, Y and Z

Given that:

$n = 20$

The number of voids (x, y and z) cannot be negative and they must be integers; So:

$x + y + z = n$

$x + y + z = 20$

Hence, the range is:

$\{(x,y,z)| x + y + z=20\}$

Solving (c): Names and values of marginal pdf of X

We have the following parameters attributed to X:

$p_1 = 5\%$ and $n = 20$

Hence, the name is: Binomial distribution

Solving (d): E(x) and Var(x)

In (c), we have:

$p_1 = 5\%$ and $n = 20$

$E(x) = p_1* n$

$E(x) = 5\% * 20$

$E(x) = 1$

$Var(x) = E(x) * (1 - p_1)$

$Var(x) = 1 * (1 - 5\%)$

$Var(x) = 1 * 0.95$

$Var(x) = 0.95$

$(e)\ P(X = 1, Y = 17, Z = 3)$

In (b), we have: $x + y + z = 20$

However, the given values of x in this question implies that:

$x + y + z = 1 + 17 + 3$

$x + y + z = 21$

Hence:

$P(X = 1, Y = 17, Z = 3) = 0$

$(f)\ P{X \le 1, Y = 17, Z = 3)$

This question implies that:

$P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) + P(X = 1, Y = 17, Z = 3)$

Because

$0, 1 \le 1$ --- for x

In (e), we have:

$P(X = 1, Y = 17, Z = 3) = 0$

So:

$P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3) +0$

$P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)$

In (a), we have:

$f_{XYZ} = P(X = x; Y = y; Z = z) = \frac{n!}{x!y!z!} * p_1^xp_2^yp_3^z$

So:

$P(X=0; Y=17; Z = 3) = \frac{20!}{0! * 17! * 3!} * (5\%)^0 * (85\%)^{17} * (10\%)^{3}$

$P(X=0; Y=17; Z = 3) = \frac{20!}{1 * 17! * 3!} * 1 * (85\%)^{17} * (10\%)^{3}$

$P(X=0; Y=17; Z = 3) = \frac{20!}{17! * 3!} * (85\%)^{17} * (10\%)^{3}$

Expand

$P(X=0; Y=17; Z = 3) = \frac{20*19*18*17!}{17! * 3*2*1} * (85\%)^{17} * (10\%)^{3}$

$P(X=0; Y=17; Z = 3) = \frac{20*19*18}{6} * (85\%)^{17} * (10\%)^{3}$

$P(X=0; Y=17; Z = 3) = 20*19*3 * (85\%)^{17} * (10\%)^{3}$

Using a calculator, we have:

$P(X=0; Y=17; Z = 3) = 0.07195$

So:

$P(X \le 1, Y = 17, Z = 3) =P(X = 0, Y = 17, Z = 3)$

$P(X \le 1, Y = 17, Z = 3) =0.07195$

$(g)\ P(X \le 1)$

This implies that:

$P(X \le 1) = P(X = 0) + P(X = 1)$

In (c), we established that X is a binomial distribution with the following parameters:

$p_1 = 5\%$ $n = 20$

Such that:

$P(X=x) = ^nC_x * p_1^x * (1 - p_1)^{n - x}$

So:

$P(X=0) = ^{20}C_0 * (5\%)^0 * (1 - 5\%)^{20 - 0}$

$P(X=0) = ^{20}C_0 * 1 * (1 - 5\%)^{20}$

$P(X=0) = 1 * 1 * (95\%)^{20}$

$P(X=0) = 0.3585$

$P(X=1) = ^{20}C_1 * (5\%)^1 * (1 - 5\%)^{20 - 1}$

$P(X=1) = 20 * (5\%)* (1 - 5\%)^{19}$

$P(X=1) = 0.3774$

So:

$P(X \le 1) = P(X = 0) + P(X = 1)$

$P(X \le 1) = 0.3585 + 0.3774$

$P(X \le 1) = 0.7359$

$(h)\ E(Y)$

Y has the following parameters

$p_2 = 85\%$ and $n = 20$

$E(Y) = p_2 * n$

$E(Y) = 85\% * 20$

$E(Y) = 17$

8 0

2 years ago

Se quiere cubrir una pared con vidrios de forma triangular. La pared mide 36 m de largo y 9V3 m de alto.

Eddi Din [679]

Based on the dimensions of the wall and the triangular glass, the number of mirrors needed is 215 mirrors.

<h3>What number of mirrors are needed?</h3>

First find the area of the wall:

= 36 x 93

= 3,348 m²

The area of the triangle, assuming it is an equilateral triangle is:

= (√3/4) x 6²

= 15.59 m²

The number of mirrors needed is:

= 3,348 / 15.59

= 215 mirrors

Find out more on the area of an equilateral triangle at brainly.com/question/1099318.

#SPJ1

4 0

1 year ago

The table shows the number of balls, by sport, in the gym. Sports Number of balls Basketball 2 Dodgeball 18 Soccerball 8 Tennis

ankoles [38]

Answer:

Option A is correct.

Step-by-step explanation:

No of Balls in Basketball = 2

No of Balls in Dodge ball = 18

No of Balls in Soccer ball = 8

No of Balls in Tennis ball = 14

$\frac{No.\:of\:Soccer\:ball}{No.\:of\:Tennis\:ball}=\frac{8}{14}=\frac{4}{7}$

Ratio of Soccer balls to Tennis balls = 4 : 7

⇒ For every 4 Soccer ball, there are 7 Tennis ball.

$\frac{No.\:of\:Basket\:ball}{No.\:of\:Dodge\:ball}=\frac{2}{18}=\frac{1}{9}$

Ratio of Basket ball to Dodge Ball = 1 : 9

⇒ For every 1 Basket ball, there are 9 Dodge balls.

Therefore, Option A is correct.

6 0

2 years ago