Bear in mind that, when it comes to trigonometric functions, the location of the exponent can be a bit misleading, however recall that sin²(θ) is really [ sin( θ )]²,
![\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2} \\\\\\ sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1} \\\\\\ sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)](https://tex.z-dn.net/?f=%5Cbf%202sin%5E2%282x%29%3D2%5Cimplies%20sin%5E2%282x%29%3D%5Ccfrac%7B2%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0Asin%5E2%282x%29%3D1%5Cimplies%20%5Bsin%282x%29%5D%5E2%3D1%5Cimplies%20sin%282x%29%3D%5Cpm%5Csqrt%7B1%7D%0A%5C%5C%5C%5C%5C%5C%0Asin%282x%29%3D%5Cpm%201%5Cimplies%20sin%5E%7B-1%7D%5Bsin%282x%29%5D%3Dsin%5E%7B-1%7D%28%5Cpm%201%29)
Answer:
x= -1
Step-by-step explanation:
3x-1=2x2 (calculate the product)
3x-1=4x (move terms)
3 x - 4 x =1 (collect the terms)
- x = 1 (change the signs)
Solution is x = -1
Answer:



Step-by-step explanation:
Given
Let the three sides be represented with A, B, C
Let the angles be represented with 
[See Attachment for Triangle]



What the question is to calculate the third length (Side B) and the other 2 angles (
)
Solving for Side B;
When two angles of a triangle are known, the third side is calculated as thus;

Substitute:
,
; 




Take Square root of both sides



<em>(Approximated)</em>
Calculating Angle 

Substitute:
,
; 




Subtract 180 from both sides


Divide both sides by -144



Take arccos of both sides



<em>(Approximated)</em>
Calculating 
Sum of angles in a triangle = 180
Hence;



Make
the subject of formula


Answer:
its option C
Step-by-step explanation: