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nlexa [21]
3 years ago
5

Kelsey keeps track of how much money she makes each time she babysits. For the last 10 jobs she made:

Mathematics
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

Mean = sum of all elements/number of elements

          = (7.5 + 10.5 + 5 + 4.5 + 3.5 + 7.5 + 4 + 10 + 7.5 + 5)/10

          = 6.5

=> Option C is correct

Hope this helps!

:)

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North
mamaluj [8]

AnswerSo first add then subtract 65

3 0
3 years ago
If vectors u,v and w ar linearly indepndnt, will u-v,v-w & u-w also be linearly indpnt? ...?
inna [77]
No they won’t be.Consider the linear combination (1)(u – v) + (1) (v – w) + (-1)(u – w).This will add to 0. But the coefficients aren’t all 0.Therefore, those vectors aren’t linearly independent.
You can try an example of this with (1, 0, 0), (0, 1, 0), and (0, 0, 1), the usual basis vectors of R3.
That method relied on spotting the solution immediately.If you couldn’t see that, then there’s another approach to the problem.
We know that u, v, w are linearly independent vectors.So if au + bv + cw = 0, then a, b, and c are all 0 by definition.
Suppose we wanted to ask whether u – v, v – w, and u – w are linearly independent.Then we’d like to see if there are non-zero coefficients in the linear combinationd(u – v) + e(v – w) + f(u – w) = 0, where d, e, and f are scalars.
Distributing, we get du – dv + ev – ew + fu – fw = 0.Then regrouping by vector: (d + f)u + (-d +e)v + (-e – f)w = 0.
But now we have a linear combo of u, v, and w vectors.Therefore, all the coefficients must be 0.So d + f = 0, -d + e = 0, and –e – f = 0. It turns out that there’s a free variable in this solution.Say you let d be the free variable.Then we see f = -d and e = d.
Then any solution of the form (d, e, f) = (d, d, -d) will make (d + f)u + (-d +e)v + (-e – f)w = 0 a true statement.
Let d = 1 and you get our original solution. You can let d = 2, 3, or anything if you want.

6 0
3 years ago
Help with this math thingy pls! <3
zvonat [6]
45.6 hope this helps
8 0
3 years ago
Somebody please help me out quick ??
scoundrel [369]
38 i think is correct

6 0
3 years ago
Read 2 more answers
Twice the smallest of three consecutive odd integers is nine more than the largest. find the integers.
polet [3.4K]
 let   x        x +2       x+4     three consecutive odd <span>integers


2x =9+ x+4   </span>Twice the smallest<span> is nine more than the largest 
 2x - x= 13

x= 13  the first 
the second integer 15   the third  17 </span>
7 0
3 years ago
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