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STALIN [3.7K]
3 years ago
15

Helppppppppp pleaseee

Mathematics
2 answers:
sukhopar [10]3 years ago
5 0

Your adding 2...so wouldn't it be x=2 or something like that.

shutvik [7]3 years ago
4 0

The rate of change is +2

as an ordered pair it would be (1,-3),(2,-1)(3,1),(4,3)

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oksian1 [2.3K]
Yes, it can be shown as 4/15.
6 0
3 years ago
Simplify the equation
Arturiano [62]

Answer:

\dfrac{16x^3-37x^2-16x+37}{x^2+2}

Step-by-step explanation:

There aren't any factors that cancel (except 3x). The best you can do is multiply it out.

\displaystyle\frac{\frac{3x^2-3}{x}}{\frac{3(x^2+2)}{16x^2-37x}}=\frac{3(x^2-1)}{x}\cdot\frac{16x^2-37x}{3(x^2+2)}\\\\=\frac{x(x^2-1)(16x-37)}{x(x^2+2)}=\frac{16x^3-37x^2-16x+37}{x^2+2}

7 0
3 years ago
Madison withdrew $22 from her bank account on Thursday and then deposited $10 on Friday. What integer represents the change in h
kotykmax [81]

Answer:

there was a -12 integer change

Step-by-step explanation:

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8 0
2 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
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IRINA_888 [86]
I would say c.-1/2 but I'm not certain
5 0
3 years ago
Read 2 more answers
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