2 years ago

Pls answer!!!!!! The sum of two numbers is 46 and the difference is 20 what are the numbers?

Mathematics

1 answer:

katen-ka-za [31]2 years ago

7 0

Answer:

33 and 13

Step-by-step explanation:

46/2 = 23

difference is 20, add 10 to one and subtract 10 from 23, giving you two numbers: 13 and 33.

You might be interested in

Simplify (7p)^3 please thanks!

Talja [164]

Answer:

how

Step-by-step explanation:

3 0

2 years ago

12s+ 3p =b There’s the question and I need help understanding it

yaroslaw [1]

Answer:

Step-by-step explanation:

8 0

3 years ago

How do you turn four and six hundredths into a decimal

Ivahew [28]

it would be 4.06 because 6/100 is 0.06 so 4.06 is your answer.

7 0

3 years ago

Each question is worth 10 pts, I will do brainliest for the person who does both and follow pls help.

In-s [12.5K]

Answer:

1. 6

pennies = 9

nickels = 5

quaters = 5

dimes = 10

Step-by-step explanation:

18/3 = 6

as we know that there are 18 scoops, and 3 per icecream, we can divide the two to get the number of ice creams

#n = #q; #q = 2#d, this is a simple ratio, you just plug in the variables to get

5n = 5q = 10d = 15 coins

24 - 15 = 9 pennies

pennies = 9

nickels = 5

quaters = 5

dimes = 10

8 0

2 years ago

PLEASE ANSWER + BRAINLIEST!! Factor completely. 4k - 20k^9 = 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

7 0

3 years ago