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3 years ago

What is the constant of variation?

Mathematics

2 answers:

KatRina [158]3 years ago

8 0

Answer:

The constant is nothing cause there is no question.

Step-by-step explanation:

ella [17]3 years ago

3 0

Answer:

The constant of variation in a direct variation is the constant (unchanged) ratio of two variable quantities. The formula for direct variation is. y=kx (or y=kx )

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What are the values of x in the equation x^2 - 6x + 9 =25

never [62]

X² - 6x +9 =25
x² -6x -16 = 0
(x+2)(x-8) = 0
x+2 = 0 or x-8 = 0
the answer will be:
x = -2 or x = 8

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3 years ago

Which expression is equivalent to - 19 - (- 27)

HACTEHA [7]

Answer:

Step-by-step explanation:

-19 - (-27)

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2 years ago

Read 2 more answers

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

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3 years ago

What are the slope of the y intercept of the line represented by the points shown on the table

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3 years ago

What is the constant of variation?​

What is the constant of variation?