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sergey [27]
3 years ago
6

Find the first 5 terms of the sequence: an = 4n-1.

Mathematics
1 answer:
Ad libitum [116K]3 years ago
5 0
#sol1

a1=1×4-1=3
a2=2×4-1=7
a3=3×4-1=11
a4=4×4-1=15
a5=5×5-1=19

#sol2

f(1)=1×4-1=3,
f(n+1)=f(n)+4,
so .... you know.
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Let <em>u</em> = (1, 0) and <em>v</em> = (0, 1). Then

<em>T</em> (<em>u</em>) = (2*1 - 3*0, 1 + 4, 5*0) = (2, 5, 0)

<em>T</em> (<em>v</em>) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)

=>   <em>T</em> (<em>u</em>) + <em>T</em> (<em>v</em>) = (-1, 9, 5)

but

<em>T</em> (<em>u</em> + <em>v</em>) = <em>T</em> (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)

=>   <em>T</em> (<em>u</em> + <em>v</em>) ≠ <em>T</em> (<em>u</em>) + <em>T</em> (<em>v</em>)

which means <em>T</em> does not preserve addition, so it is not linear.

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Answer:

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Step-by-step explanation:

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<h3>Hope it is helpful...</h3>
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Step-by-step explanation:

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