Answer:
A situation represents a proportional relationship if you can write equivalent ratios of related quantities in that situation.
Q
Question 1:
Slope = 1/5
y = mx + c
y = 1/5 x + c
at point (5, -1)
-1 = 1/5 (5) + c
- 1= 1 + c
c = - 2
y = 1/5x - 2
5y = x - 10
Question 2:
slope = (9-5)/(3-1)
Slope = 2
y = mx + c
y = 2x + c
at point (1, 5)
5 = 2(1) + c
c = 5 - 2
c = 3
y = 2x + 3
Answer:
what is the question asked?
Step-by-step explanation:
Kade worked for 15 hours and theo worked for 12
Answer:
- 5, 2, 9, 16 and d = + 7
Step-by-step explanation:
to obtain the first four terms substitute n = 2, 3, 4 into the recursive formula
f(1) = - 5 ← given
f(2) = f(1) + 7 = - 5 + 7 = 2
f(3) = f(2) + 7 = 2 + 7 = 9
f(4) = f(3) + 7 = 9 + 7 = 16
common difference d = 16 - 9 = 9 - 2 = 2 - (- 5) = 7
