Answer:
<em>Another point on the graph is
.</em>
Step-by-step explanation:
To find another point on the graph, we have to find the equations of the line.
In first place, we need to calculate the slope, which definition is:

The problem gives us the two points needed to find the slope:

Now, we use the slope and one point to find the equation with the point-slope formula:

The independent term is missing, this means that it's zero. So, when a linear function doesn't have the independent terms, we know that the line will pass through the origin of the system, which is 
Therefore, another point on the graph is 
(The graph is attached. The slope is two high, that's why the line is almost vertical).