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Lerok [7]
3 years ago
15

A soccer player is running at 6m/s. He then stumbled over an opponent's foot falling, in Rolling to a stop. This took four secon

ds. What it was his acceleration?
Mathematics
2 answers:
mixas84 [53]3 years ago
4 0
-1.5m/s² or - 1.5ms¯2
Tresset [83]3 years ago
4 0

Answer:

His acceleration was -1/5 m/s²

Step-by-step explanation:

We can find the acceleration by using the formula to find the final velocity in terms of initial velocity and acceleration and then solving for a. The formula is   V2 = V1 + (a)(t) where V2 is final velocity, V1 is initial velocity and t is time in seconds.

We are going to substitute the values given in the problem:

V2 = 0 m/s

V1 = 6 m/s

t = 4 seconds

V2=V1+at\\0=6+a4\\0=6+4a\\-6=4a\\-6/4=a\\-1.5=a

Therefore, his acceleration was -1.5 m/s²

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Hi, help ASAP please.
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Answer:

17.3

Step-by-step explanation:

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7 0
2 years ago
The water reaches a max height when the horizontal distance from the firefighter to the building is approximately __m. Round to
elena-s [515]

The horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

<u>Explanation:</u>

Given:

h(x) = -0.026x² + 0.563x + 3

where,

h(x) is the height of the water

Initial speed, u = 14m/s

angle, θ = 30°

(a)

Horizontal distance = ?

h(x) = ax² + bx + c

the vertex is found at x = -b/2a

where,

x = distance to the maximum height

As compared to the equation given:

a = -0.026

b = 0.563

Thus,

x = \frac{-0.563}{2 X -0.026} \\\\x = \frac{0.563}{0.052}\\ \\x = 10.83m

Therefore, horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

3 0
3 years ago
Which of the following could be the perimeter of a rectangle with an area of 16 square inches?
emmasim [6.3K]

Answer:

16 inches

Step-by-step explanation:

6 0
3 years ago
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Some animals on farms eat hay to get energy. A horse can eat twenty pounds of hay each day. Write and evaluate an expression to
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7 0
3 years ago
2 - ( - 4.51) = _____________
murzikaleks [220]
Your answer is, 6.51.

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