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Lerok [7]
3 years ago
15

A soccer player is running at 6m/s. He then stumbled over an opponent's foot falling, in Rolling to a stop. This took four secon

ds. What it was his acceleration?
Mathematics
2 answers:
mixas84 [53]3 years ago
4 0
-1.5m/s² or - 1.5ms¯2
Tresset [83]3 years ago
4 0

Answer:

His acceleration was -1/5 m/s²

Step-by-step explanation:

We can find the acceleration by using the formula to find the final velocity in terms of initial velocity and acceleration and then solving for a. The formula is   V2 = V1 + (a)(t) where V2 is final velocity, V1 is initial velocity and t is time in seconds.

We are going to substitute the values given in the problem:

V2 = 0 m/s

V1 = 6 m/s

t = 4 seconds

V2=V1+at\\0=6+a4\\0=6+4a\\-6=4a\\-6/4=a\\-1.5=a

Therefore, his acceleration was -1.5 m/s²

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a geometric sequence has an initial value of 25 and a common ratio of 1.8. Write a function to represent this sequence . Find.th
Debora [2.8K]
Use the formula

a_n = a_1•r^(n-1)

a_23 = 25•(1.8)^(23 - 1)

Can you finish?
8 0
3 years ago
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

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7 0
1 year ago
Need help with this question
ElenaW [278]

Answer: its 432cm=m cubed

Step-by-step explanation:

im not telling you

3 0
3 years ago
Read 2 more answers
Question 2 (Essay Worth 10 points)
Luba_88 [7]

Answer:

Sam is incorrect.

Step-by-step explanation:

Using Pythagorean Theorem, we can find the length of diagonal SQ as 13.4 (6^2 + 12^2 = c^2, 36 + 144 = c^2, sqrt(180) = c, c is approx 13.4). We can do the same for diagonal OM (6^2 + 6^2 = c^2, 36 + 36 = c^2, 72 = c^2, sqrt(72) = c, c is approx 8.5). Sam is therefore incorrect because 13.4 is not double of 8.5.

3 0
2 years ago
Perform the following calculations without rewriting the numbers in decimal form.
RSB [31]

Answer:

Answer will be 140\times 10^{13}

Step-by-step explanation:

We have to perform the calculation (1.42\times 10^{15}-2\times 10^{13}) without changing into decimal

1.42\times 10^{15} can be written as 142\times 10^{13}

So 1.42\times 10^{15}-2\times 10^{13}=(142\times 10^{13}-2\times 10^{13})

Now taking 10^{13} common

10^{13}(142-23)=140\times 10^{13}

6 0
3 years ago
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