One of the fractions that’s equal to
is ![\frac{12}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B16%7D)
<u>Solution:</u>
Given that , we have to find fractions which has the same value as that of the fraction
Now, we know that, there are several fractions with values equal to
To find them, just multiply the numerator and denominator by the same number.
![\begin{array}{l}{3 \times 2=6} \\\\ {4 \times 2=8}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B3%20%5Ctimes%202%3D6%7D%20%5C%5C%5C%5C%20%7B4%20%5Ctimes%202%3D8%7D%5Cend%7Barray%7D)
Therefore,
is equal to ![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
We can do the same with 4, to get
, or any other number beyond that.
Hence, one of the fractions that’s equal to
is ![\frac{12}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B16%7D)
Total earning in the summer = $1440
Step-by-step explanation:
Earning per hour for Samuel = $7.50
No. of hours worked in a day = 6
Earning for a day = Earning per hour for Samuel *No. of hours worked in a day
Earning for a day = $7.50 *6 = $45
___________________________________________________
No of days worked in a week by Samuel = 4
Earning for week = Earning for a day *No of days worked in a week by Samuel
Earning for week = $45*4 = $180
_____________________________________________________
No. of weeks worked in summer = 8
Total earning in the summer = Earning for week *No. of weeks worked in summer
Total earning in the summer = $180*8 = $1440 (Answer)
*NOT MY ANSWER SOMEONE ALREADY ANSWERED THIS***
Answer:
1.42
Step-by-step explanation:
In all these expressions you have a power of a power.
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
.
11) (n^4)^8 = n^(4×8) = n^32
13) (q^10)^10 = q^(10×10) = q^100
15) (x^3)^-5 = x^[3×(-5)] = x^(-15)
17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5
<span>
19) (c^3)^5(d^3)^0 = c^(3</span>×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15
Substitute <em>u</em> = <em>t</em> ³/2592 and d<em>u</em> = <em>t</em> ²/864 d<em>t</em>. Then
![P(T)=1-\displaystyle\int_0^T f(t)\,\mathrm dt=1-\displaystyle864\left(1.1574\times10^{-3}\right)\int_0^{\frac{T^3}{2592}}e^{-u}\,\mathrm du](https://tex.z-dn.net/?f=P%28T%29%3D1-%5Cdisplaystyle%5Cint_0%5ET%20f%28t%29%5C%2C%5Cmathrm%20dt%3D1-%5Cdisplaystyle864%5Cleft%281.1574%5Ctimes10%5E%7B-3%7D%5Cright%29%5Cint_0%5E%7B%5Cfrac%7BT%5E3%7D%7B2592%7D%7De%5E%7B-u%7D%5C%2C%5Cmathrm%20du)
The probability that a 12 hour surgery is successful is <em>P</em> (12), so letting <em>T</em> = 12 gives
![P(12)\approx1-\displaystyle\int_0^{\frac23}e^{-u}\,\mathrm du\approx e^{-\frac23} \approx \boxed{0.5134}](https://tex.z-dn.net/?f=P%2812%29%5Capprox1-%5Cdisplaystyle%5Cint_0%5E%7B%5Cfrac23%7De%5E%7B-u%7D%5C%2C%5Cmathrm%20du%5Capprox%20e%5E%7B-%5Cfrac23%7D%20%5Capprox%20%5Cboxed%7B0.5134%7D)