Answer:
How many of these passwords contain at least one occurrence of at least one of the five special characters?
Answer:
7/20
Step-by-step explanation:
You have: 3/5 - 1/4
When you have different denominator:
1) Multiply in cross. The numerator of the first fraction is multiplied by the denominator of the second, and the denominator of the first by the numerator of the second. Both multiplications are subtracted.
3/5 - 1/4 = [(3*4) - (5*1 )] / ...
2) The denominators of the two fractions are multiplied.
3/5 - 1/4 = [(3*4) - (5*1 )]/(5*4
)
3) Resolve operations
= (12-5)/20
= 7/20
X= -2/5
SOLUTION
25x^2 + 20x + 4 = 0
(5x + 2)^2 = 0
5x + 2 = 0
x= -2/5
Hope this helps! :))
Answer:
m > 3 for 2 solutions.
m = 3 for one solution.
Step-by-step explanation:
mx^2 - 2mx + 3 = 0
For 2 solutions the discriminant b^2 - 4ac > 0 so we have
(-2m)^2 - 4*m* 3 > 0
4m^2 - 12m > 0
4(m^2 - 3m) > 0
m^2 - 3m > 0
m(m - 3) > 0
m > 3 - this is the result for 2 solutions.
For one solution the discriminant = 0
so m(m - 3) = 0
and m = 3 for 1 solution.