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3 years ago

Round 218 to the nearest ten

Mathematics

2 answers:

g100num [7]3 years ago

6 0

Rounding 218 ⇒ 220.

Hoped this helped.

~Bob Ross®

rewona [7]3 years ago

5 0

It rounds to the nearest 10

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the area of a bathroom floor is 24 Sq ft.If the width of the bathroom is 6feet, what is the length of the bathroom?

Vaselesa [24]

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3 years ago

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Which expression is equivalent to (3x+2)(3x-5)?

Lemur [1.5K]

Answer:

9x^2-9x-10

Step-by-step explanation:

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3 years ago

Nearing the end of his holiday preparations Richard has only one piece of Wrapping paper left for three remaining gifts. The rem

Ivanshal [37]

<h2>Hello!</h2>

The answer is:

The dimensions of the paper for Gift C, are: 25" x 12"

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$GiftCArea=300inch^{2}$

To solve the problem, we need to calculate the total area of the remaining paper, and then, subtract it from the paper used for the gift A and B.

We know that:

$GiftA=TotalPaperArea*\frac{2}{5}\\\\GiftB=TotalPaperArea*\frac{1}{3}$

Now, the paper for Gift C will be:

$GiftCArea=(TotalPaperArea)-(PaperArea*\frac{2}{5}+PaperArea*\frac{1}{3})$

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$TotalArea=25inch*45inch=1125inch^{2}$

Now, calculating the area of the paper for Gift A and B, we have:

$GiftA=1125inch^{2}*\frac{2}{5}=450inch^{2}\\\\GiftB=1125inch^{2}*\frac{1}{3}=375inch^{2}$

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$GiftCArea=(TotalPaperArea)-(PaperArea*\frac{2}{5}+PaperArea*\frac{1}{3})$

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$GiftCArea=300inch^{2}$

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$GiftCArea=Height*Width\\\\Width=\frac{GiftCArea}{25inches}=\frac{300inches^{2} }{25inches}=12inches$

Hence, the dimensions of the paper for Gift C, are: 25" x 12".

Have a nice day!

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3 years ago

Darren is playing board game. a move forward is a positive value. A move backward is a negative value. He wrote an inequality co

Vitek1552 [10]

Answer:

<u>Step-by-step explanation:</u>

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3 years ago

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Bogdan [553]

Answer:

You would need to use the rule (-y, x) to solve this. So, take each point and change the coordinates to the rule above.

Explanation:

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