1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kondor19780726 [428]
3 years ago
7

Please help me me me

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0
What can I help you with
You might be interested in
a square prism container with a base of 5 cm by 5 cm partially filled with water. you drop a clump of metal with mass 525 g into
ruslelena [56]
Any selection choices?
4 0
3 years ago
A middle school took all of its 6th grade students on a field trip to see a play at a theater that has 4600 seats. The students
ahrayia [7]

Answer:

4232

Step-by-step explanation:

92% x 4600

4232

7 0
2 years ago
In the triangle below, x=7 yards. What is the value of y
victus00 [196]

Answer: \\  \tan(30°)  =  \frac{x}{y}  =  \frac{7}{y}  \\ \Leftrightarrow y =  \frac{7}{ \tan(30°) }  =  \frac{7}{ \frac{1}{ \sqrt{3} } }  = 7 \sqrt{3}  \: yards

7 0
3 years ago
A research team conducted a study showing that approximately 25% of all businessmen who wear ties wear them so tightly that they
Sonbull [250]

Answer:A) 0.9866

Step-by-step explanation:

Probability of at least one tie is too tight is

Probability of tight tie 25/100

Probability of not a tight tie is 1-25/100=3/4

=1-(3/4)^15=0.9866

B)0.764

C)0.013

D)0.236

Method 2

This is binomial probability.

n=15 (number of businessmen

p=.25 (probability that a businessman wears the tie so tightly

A)

x = number of businessmen out of 15 who wears the tie so tightly

P( at least 1) = P( x >= 1) = 1-P(x=0)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P( at least 1) = 1- 0.013363 = 0.9866

B)

P(more than 2) = P( x > 2) = 1-P( x=0)-P(x=1)-P(x=2)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P(x=1) = 15C1 (.25)^1 (.75)^14 = 0.066817

P(x=2) = 15C2 (.25)^2 (.75)^13 = 0.155907

1-P( x=0)-P(x=1)-P(x=2) = 1 - 0.013363 - 0.066817 - 0.155907 = 0.763912

C)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

D)

P( at least 13) = P(x=13)+P(x=14)+P(x=15)

P(x=13)= 15C13 (.25)^13 (.75)^2 = 0.000001

P(x=14)= 15C14 (.25)^14 (.75)^1 = 0.000000

P(x=15)= 15C15 (.25)^15 (.75)^0 = 0.000000

P(x=13)+P(x=14)+P(x=15) = .000001+.000000+.000000 = 0.000001

4 0
3 years ago
Read 2 more answers
Simplify and give me steps please.<br> (5m^4/3 x 5n^1/4) (m^1/3 x 2n^1/8)
PtichkaEL [24]

Answer:

(25m^4n^1/12)(m^1n^1/12)

Step-by-step explanation:

Re-order terms to the left.  

(5*5m^4/3 * n^1/4) (m^1/3*2n^1/8)

Combine terms

(5*5m^4n^1/3/4)     2m^1n^1/3/3/8    

Multiply

(25m^4n^1/3/4)       2m^1n^1/3/3/8    

(25m^4n^1/3 * 4)    2m^1n^1/3/3*8    

(25m^4n^1/12).        2m^1n^1/3/24

cancel common terms in both num and denominator

   

Final - (25m^4n^1/12) (2m^1n^1/12).

4 0
3 years ago
Other questions:
  • What is the solution to this equation? 3(4x + 3) = 2x - 5(3 - x) + 2 A. B. C. D.
    13·1 answer
  • I can't seem to get this one right, Any help?
    12·1 answer
  • hey brainly users i would appreciate some help on making and solving a elimination problem, "There are 46 first graders on a fie
    5·1 answer
  • Samuel is solving the equation 3 (x minus 1) + 4 = 2 minus (x + 3). Which equivalent equations might Samuel use? Check all that
    9·1 answer
  • Pls Help anyone. Ill will give brainliest and you will get 45 points pls anyone pls ㏒㏒㏒㏒㏒㏒
    6·1 answer
  • <img src="https://tex.z-dn.net/?f=Compare%20%5C%3A%20the%20%5C%3A%20graphs%20%5C%3A%20of%20%5C%5C%203x%20-%204y%20%3D%208%20%5C%
    5·1 answer
  • Correct answer gets 5 star
    14·2 answers
  • Please help. I will give brainliest to the best answer. Thank you!
    10·1 answer
  • Mrs, O'Neil has 2 times as many markers as colored pencils. The total number of markers and colored pencils is 18. How many mark
    11·1 answer
  • Use the numbers 6 2 9 5 2 3<br> to make 36.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!