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babunello [35]
3 years ago
12

Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.

Mathematics
1 answer:
algol133 years ago
4 0
Answers:
x = 24
y = 8√3
Explanation:

1) Since, the given triangle is a right triangle, and you have both an angle and the hypotenuse length, you can use some trigonometric ratios to find the variables.

2) The variables given represent:

x: adjacent-leg to angle 30°
y: opposite length to angle 30°

3) sine ratio:

sin 30° = opposite-leg / hypotenuse = y / (16√3)

⇒ y = 16√3 sin 30° = 16√3 × (1/2) = 8√3

4) cosine ratio

cos 30° = adjacent-leg / hypotenuse = x / (16√3)

⇒ x = 16√3 cos 30° = 16√3 (√3 / 2) = 16 × 3 / 2 = 24

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Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc
drek231 [11]

Answer:

C. 178−−−√ m

Step-by-step explanation:

Given the following :

v = final velocity (in m/s)

u = initial velocity (in m/s)

a = acceleration (in m/s²)

s = distance (in meters).

Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters

Using the 3rd equation of motion :

v^2 = u^2 + 2as

v^2 = 8^2 + 2(3)(19)

v^2 = 64 + 114

v^2 = 178

Take the square root of both sides :

√v^2 = √178

v = √178

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3 years ago
A florist has 49 red roses and 63 white roses. The florist wants to put an equal number of red roses in each centerpiece, along
RideAnS [48]
7..
49 can be equally divided by seven, which means there would be 9 red roses in each center piece. And 63 can be equally divided by 7 which means there would by 7 white roses in each center piece.
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3 years ago
Find the area of an equilateral triangle with side 8
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Hello! I believe the answer is 27.71.


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6 0
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Which type of programmer designs programs for applications executed on the internet
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3 years ago
Determine the equation of quadratic function represented by the table of value below.
Svetllana [295]

Answer:

A

Step-by-step explanation:

The general rule for the quadratic function is

y=ax^2+bx+c

Use the data from the table:

y(0)=6\Rightarrow 6=a\cdot 0^2+b\cdot 0+c\\ \\y(1)=4\Rightarrow 4=a\cdot 1^2+b\cdot 1+c\\ \\y(-1)=10\Rightarrow 10=a\cdot (-1)^2+b\cdot (-1)+c

We get the system of three equations:

\left\{\begin{array}{l}c=6\\ \\a+b+c=4\\ \\a-b+c=10\end{array}\right.

From the first equation

c=6, then

\left\{\begin{array}{l}a+b=-2\\ \\a-b=4\end{array}\right.

Add these two equations:

a+b+a-b=-2+4\\ \\2a=2\\ \\a=1

So,

b=-2-a=-2-1=-3

The quadratic function is

y=1\cdot x^2-3x+6\\ \\y=x^2-3x+6

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3 years ago
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