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3 years ago

Range represents which of the following?

Mathematics

2 answers:

ElenaW [278]3 years ago

7 0

Answer:

C. y values

Step-by-step explanation:

The domain of a function would be it's inputs. The inputs are the x-values in a function.

The range of a function would be it's outputs. The outputs are the y-values in a function.

For example:

{(2,3) (4,2) (6, 10) (3, 8)}

{2,3,8,10} would be your range, since they are the y-values of the points.

Brainialiest Appreciated!

NikAS [45]3 years ago

4 0

Answer: c. y values

Step-by-step explanation:

x-values are known as domains or otherwise known as the horizontal line in a graph. y-values are known as the range or otherwise known as the vertical line in a graph.

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Ymorist [56]

Answer:

(x+6)(x-1)

Step-by-step explanation:

factor using the x-box method

7 0

2 years ago

Read 2 more answers

Explain the distance formula. Then use it to calculate the

Alex777 [14]

Answer:

$dAB=10\ units$

Step-by-step explanation:

we know that

The distance formula is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(1, 1) and B(7, −7)

Let

(x1,y1)=A(1, 1)

(x2,y2)=B(7, −7)

substitute the given values in the formula

$dAB=\sqrt{(-7-1)^{2}+(7-1)^{2}}$

$dAB=\sqrt{(-8)^{2}+(6)^{2}}$

$dAB=\sqrt{64+36}$

$dAB=\sqrt{100}$

$dAB=10\ units$

6 0

2 years ago

Read 2 more answers

Help with these precalculus problems, please.

likoan [24]

Yay, easy peasy, nice refresher

53. evaluate for x=infinity
we get 100/(infiniy^2-5) which is basically 100/infinity which is a very small number so about 0

54.
vertical assemtotes, neato
that is where the denomenator equals 0
but wait, simplify first
ok, fraction is simplified (anything factored out would be a hole)
so set the denom to 0 and solve
x^2-5=0
(x-√5)(x+√5)=0
x=-√5 and √5
vertical assemtotes at x=-√5 and x=√5

55. horizontal assemtotes
for the function p(x)/f(x)

if p(x) has lower degree than f(x) then y=0 is the horizontal assemtote

if p(x) has equal degree to f(x) then divide the leading coefients of p(x) and f(x)

if p(x) has greater degree than f(x) then we got slant assemtotes

100/(x^2-5)
100 has lower degree than x^2
y=0 is the horizontal assemtote

56. evalate for x=-5
we get -150/-10=150/10=15
the limit is 15

57. that negative on the right side means that we must approach it from the left
let's see if we can factor out the denomenator
nope
so go and evaluate values like 4, 4.5, 4.9, etc, approaching x=5 from the left
we keep getting smaller and smaller valuse
this make sense because as x approaches 5, we get 30(c)/(c-5) where c is close to 5, and as c appraoches 5 very close, the top part is appraoching 150 but the bottom approaches a very small negative number, and if we do something like 150/-0.00000000001, we get a very negative number
the limit is negative infinity

alternately, you could figure that there is a vertical assemtote at x=5 so we can see that if we aproximaate closer and closer values, we get smaller values. so from what we know about assemtotes, expecially vertical ones, we say that it approaches negative infinity

58.
evalauating we get infintity/inifinty, not helpful
hmmm, is there a horizontal assemtote to help us?
the degree of top is higher so we got a slant assemtote
the only way is to use long division to divide the top by the bottom (see attachment)
we get
$\frac{1}{2}x-\frac{1}{4}+\frac{\frac{1}{4}}{2x+1}$
the slant assemtote is $y=\frac{1}{2}x-\frac{1}{4}$
as you can see, as x approaches infinity, y also will approach infinity

ANSWERS:
53. 0
54. VA is x=-√5 and x=√5
55. HA is y=0
56. the limit is 15
57. the limit is -∞
58. the limit is ∞