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3 years ago

Find 3 different possibile pairs of values for a and b

Mathematics

2 answers:

anygoal [31]3 years ago

6 0

Hello! Essentially you are trying to find a linear function. For example, a linear function is a function that increases or decreases in some type of relationship between each pair consistently. To answer your question, one example could look like this...

Lastbenchstudent basically nailed the linear equation but I could elaborate from his work and answer your question in a different way.

A = 3, B = 18

A = 2, B = 9

A = 1, B = 4.5

To explain my answer, I basically divided B every time A decreased. As A decreased by 1, B decreased by half the amount!

Lynna [10]3 years ago

3 0

a=1, b =18

a=2, b = 9

a = 3 , b = 6

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Wish someone can do this for me.

Makovka662 [10]

Given : Two inequality is given to us . The inequality is v + 8 ≤ -4 and v - 6 ≥ 10 .

To Find : To write those two inequality as a compound inequality with integers .

Solution: First inequality given to us is v + 8 ≤ -4 . So let's simplify it ;

⇒ v + 8 ≤ -4 .

⇒ v ≤ -4 - 8.

⇒ v ≤ -12 .

Now , on simplifying the second inequality ,

⇒ v - 6 ≥ 10 .

⇒ v ≥ 10 + 6.

⇒ v ≥ 16 .

Hence the required answer will be :

$\Large{\boxed{\red{\bf \blue{\dag} v\leqslant -12 \:\:or\:\:v\geqslant 16}}}$

First one implies that v is less than or equal to -12 whereas the second one implies that v is greater than or equal to 16 .

5 0

2 years ago

Find the distance between the points

Tasya [4]

Answer:

5 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (2, 1) and (x₂, y₂ ) = (6, 4)

d = $\sqrt{(6-2)^2+(4-1)^2}$

= $\sqrt{4^2+3^2}$

= $\sqrt{16+9}$

= $\sqrt{25}$

= 5

3 0

2 years ago

Read 2 more answers

Find the length of XY. Imported Asset 4 8 16 11.3

kompoz [17]

Answer: 8 (The second option).

Step-by-step explanation:

1. To solve this exercise you draw a line to a point O, this lines will bisect the angle of Z∠60°. Then will obtain two into two right triangles with two angles of 30° at the point Z.

2. The lenght XY will be twice the lengt XO or YO.

3. Let's calclate XO as following:

$sin(30)=\frac{XO}{8}\\XO=4$